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    <p>No. Typically, undelimited continuations (eg created with Scheme's <code>call/cc</code>) jump when you invoke the <code>continuation</code>, not when you call <code>call/cc</code> (aka <code>call-with-current-continuation</code>).</p> <p>So, fleshing out your example:</p> <pre><code>continuation savedk; void foo(int arg) { ... } int bar() { ... call/cc(handler) // after call/cc println "after call/cc" ... } void handler(continuation k) { savedk = k } foo ( bar() ) // after foo invocation </code></pre> <ol> <li><p>Execution starts. We enter <code>bar</code> (we haven't entered <code>foo</code> yet; we'll do that when we get done with <code>bar</code>).</p></li> <li><p>When we hit the call to <code>call/cc</code> in <code>bar</code>, the "program context" is turned into an object called a continuation. At this point, the program context consists of "finish executing <code>bar</code>, then call <code>foo</code> on the result, and then do whatever comes after the <code>foo</code> invocation". The continuation is passed to the function given as an argument to <code>call/cc</code>, which is <code>handler</code> in my example above.</p></li> <li><p><code>handler</code> does something with the continuation. Let's assume it stores it in a global variable. Then it returns to the point right after the <code>call/cc</code> call, still inside of <code>bar</code>.</p></li> <li><p>Let's say we print something out at this point. Then <code>bar</code> finishes and we call <code>foo</code>, and it finishes.</p></li> <li><p>If we now apply the continuation in <code>savedk</code>, control jumps back into <code>bar</code> and restores the program context to "finish executing <code>bar</code>, then call <code>foo</code> on the result, and then do whatever comes after the <code>foo</code> invocation". So we get another line printed. In fact, if we don't clear the <code>savedk</code> variable or test some other state, we might get an infinite loop if "do whatever comes after the <code>foo</code> invocation" is call <code>savedk</code> again!</p></li> </ol>
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