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    <p>I don't know about the analysis of the memory usage, but you might try this to get it to work without running out of memory. You'll sort into a new file which is accessed using a memory mapping (I've been led to believe this will work efficiently [in terms of memory]). Mmap has some OS specific workings, I tested this on Linux (very small scale).</p> <p>This is the basic code, to make it run with a decent time efficiency you'd probably want to do a binary search on the sorted file to find where to insert the line otherwise it will probably take a long time.</p> <p>You can find a file-seeking binary search algorithm in <a href="https://stackoverflow.com/questions/744256/reading-huge-file-in-python">this question</a>.</p> <p>Hopefully a memory efficient way of sorting a massive file by line:</p> <pre><code>import os from mmap import mmap input_file = open('unsorted.txt', 'r') output_file = open('sorted.txt', 'w+') # need to provide something in order to be able to mmap the file # so we'll just copy the first line over output_file.write(input_file.readline()) output_file.flush() mm = mmap(output_file.fileno(), os.stat(output_file.name).st_size) cur_size = mm.size() for line in input_file: mm.seek(0) tup = line.split("\t") while True: cur_loc = mm.tell() o_line = mm.readline() o_tup = o_line.split("\t") if o_line == '' or tup[0] &lt; o_tup[0]: # EOF or we found our spot mm.resize(cur_size + len(line)) mm[cur_loc+len(line):] = mm[cur_loc:cur_size] mm[cur_loc:cur_loc+len(line)] = line cur_size += len(line) break </code></pre>
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