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    <p><strong>Function:</strong></p> <pre><code>- (NSString *)theFunction:(float)input { NSArray * array = [NSarray initWithObjects:nil,nil@"1/8",nil,@"1/4",] int fractions = lroundf((input - (int)input)/((float)1/(float)16)); if(fractions == 0 || fractions == 16) { return [NSString stringWithFormat:@"%d",lroundf(input)]; } else { return [NSString stringWithFormat:@"%d %d/16",(int)input,fractions]; } } </code></pre> <p><strong>Note:</strong></p> <p>The <code>if</code> statement converts <code>5 0/16</code> into <code>5</code> and <code>5 16/16</code> into <code>6</code>.<br> If you prefer the <code>5 0/16</code> and <code>5 16/16</code> notation, replace the <code>if</code> statement by:</p> <pre><code>return [NSString stringWithFormat:@"%d %d/16",(int)input,fractions]; </code></pre> <p><strong>EDIT:</strong> <em>(by Jason)</em></p> <pre><code>//Just to make it a little sweeter! - (NSString *)theFunction:(float)input { int fractions = lroundf((input - (int)input)/((float)1/(float)16)); if(fractions == 0 || fractions == 16) { return [NSString stringWithFormat:@"%d",lroundf(input)]; } else if(fractions == 2) { return [NSString stringWithFormat:@"%d 1/8",(int)input]; } else if(fractions == 4) { return [NSString stringWithFormat:@"%d 1/4",(int)input]; } else if(fractions == 6) { return [NSString stringWithFormat:@"%d 3/8",(int)input]; } else if(fractions == 8) { return [NSString stringWithFormat:@"%d 1/2",(int)input]; } else if(fractions == 10) { return [NSString stringWithFormat:@"%d 5/8",(int)input]; } else if(fractions == 12) { return [NSString stringWithFormat:@"%d 3/4",(int)input]; } else if(fractions == 14) { return [NSString stringWithFormat:@"%d 7/8",(int)input]; } else { return [NSString stringWithFormat:@"%d %d/16",(int)input,fractions]; } } </code></pre> <p><strong>EDIT</strong> (Response to edit by Jason)</p> <p>I optimized your code, this way it's much cleaner.<br> Also check the code below, I think it's more efficient to use an array.</p> <pre><code>- (NSString *)theFunction:(float)input { NSArray * array = [[NSArray alloc] initWithObjects: @"",@"",@"1/8",@"",@"1/4",@"",@"3/8",@"",@"1/2",@"",@"5/8",@"",@"3/4",@"",@"3/4",@"",@"7/8",@"",nil]; int fractions = lroundf((input - (int)input)/((float)1/(float)16)); if(fractions == 0 || fractions == 16) { return [NSString stringWithFormat:@"%d",lroundf(input)]; } else { if([[array objectAtIndex:fractions] isEqualToString:@""]) { return [NSString stringWithFormat:@"%d %d/16",(int)input,fractions]; } else { return [NSString stringWithFormat:@"%d %@",(int)input,[array objectAtIndex:fractions]]; } } } </code></pre>
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    1. POFinding the numerator of a float's fractional value, given a specific denominator
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    1. COis "input" where the variable would go? wouldn't you need to set the text of variable?
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    2. CO+1 for code. I don't have an Objective-C compiler in front of me, and would have been too lazy anyway.
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    3. CO@Jason. You can simply paste the function inside your implementation file (the .m file) and then call it like `NSString * result = [self theFunction:5.03];`.
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