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    <p>Try representing the tree with <code>Model</code> as the node and each node containing a <code>Collection</code> of its child nodes: </p> <pre><code>var CTreeDataItem = Backbone.Model.extend({ initialize: function() { if (Array.isArray(this.get('items'))) { this.set({items: new CTreeDataItemChildren(this.get('items'))}); } } }); // children collection var CTreeDataItemChildren = Backbone.Collection.extend({ model: CTreeDataItem }); // create var treeData = new CTreeDataItemChildren(treeJs); // access treeData.at(0).get('items').at(1).get('title') // returns "Item2" </code></pre> <hr> <p><strong>EDIT 2011-05-18:</strong> If you want to flatten the tree and maintain a reference to the parent that each node had in the tree:</p> <pre><code>// flatten the tree outside of Backbone. Alternatively, // you could override the constructor of the CTree collection // to provide encapsulation function flatten(parentID, arr) { var out = []; for (var i = 0; i &lt; arr.length; i++) { var node = arr[i]; node.parentID = parentID; out.push(node); if (Array.isArray(node.items)) Array.prototype.push.apply(out, flatten(node.id, node.items)); delete node.items; } return out; } // remove above code that would have provided nesting var CTreeDataItem = Backbone.Model.extend({}); // children collection, as before var CTreeDataItemCollection = Backbone.Collection.extend({ model: CTreeDataItem }); // create var treeData = new CTreeDataItemChildren(flatten('', treeJs)); // as before, but now there's the 'parentID' FK treeData.at(3).get('parentID') // returns "ti1" </code></pre> <p>Hope that's what you're after.</p>
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    1. COWell, there are different ways to flatten the tree structure. I rather go for relational db format where items have parentId. Or I can sort items and keep their indentation. I was only curious why I can't load tree data in json format creating nested collections and models from the same type.
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    2. COThe above code does load tree data into collections of models containing nested collections of models, so... not sure I follow. So what you're looking for is to flatten the tree, with child nodes put on the same axis as their parent, with some 'foreign key' referencing its parent it had in the ex-tree structure?
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    3. COIn fact I choose a 3rd solution. To reorganize my backend data in list format that. This is actually what your function flatten does but without its need :)
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