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    <p>The behavior of your code depends critically on the compiler you are using. More precisely, it depends on which version of language specification your compiler implements.</p> <p>For C++98 compilers, both declarations have identical effect on the final values of the objects being declared: the <code>str</code> member should become empty, while the <code>num</code> members should contain unpredictable value. In both cases the actual initialization is <em>default-initialization</em> performed by a compiler-provided default constructor of class <code>temp</code>. That default constructor initializes <code>str</code>, but leaves <code>num</code> uninitialized.</p> <p>For C++03 compilers the behavior is different. There's no difference for <code>temp1</code> object (its <code>num</code> is still unpredictable). But <code>temp2</code> initialization is handled differently. In C++03 the <code>()</code> initializer triggers the new kind of initialization - so called <em>value-initialization</em>. Value-initialization ignores the compiler-provided default constructor of the top level object, and instead works directly on its subobjects (data members in this case). So the <code>temp2</code> object is effectively initialized by value-initialization, which also sets the <code>num</code> member to zero (in addition to initializing <code>str</code> with an empty string). For this reason, <code>temp2.num</code> ends up being zero in C++03 compilers.</p> <p>If in your experiments you observed consistent zero in <code>temp2.num</code>, it means that your compiler follows the C++03 specification in this respect.</p>
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    1. COSo MSVC2010 follows C++98, huh? Strange that they lag behind..
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    2. CO+1 that really clarified the accepted answer, thanks!
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