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2011-05-10T23:35:15.223
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I will try to explain an example of pre and post increment from which you can solve the question posted yourself. <pre><code>#include <iostream> void foo(int num) { std::cout << num << "\n" ; } int main() { int number = 10 ; foo( number++ ) ; foo( ++number ) ; foo( number + 1 ) ; getchar() ; return 0 ; } </code></pre> Output: <blockquote> 10 12 13 </blockquote> Why 10? <pre><code>foo( number++ ) ; </code></pre> Post-increment operation is done on number. Meaning, value of number is first passed to <code>foo</code> and then the value of number is incremented upon <code>foo</code> return. So, after function return, number is 11. Why 12? <pre><code>foo( ++number ) ; </code></pre> Pre-increment operation is done on number. Meaning, before even call to <code>foo</code>, the value of <code>number</code> is incremented to 12. And then it is passed to <code>foo</code>. So, even after the function return, number is still 12. Why 13? It's just straight forward. Value of number is not modified but passed a value adding 1 to the value of number. In this process, number is not modified. So, even after function return, number is still 12. Hope this helps to solve the problem yourself ( though in your case it is paper-pencil exercise ) :)
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1. POIncrementing pointers in C++
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1. USMahesh
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1. CO@user - Since you need to understand recursion and also the scope of the variables in the recursion tree, this thread should be helpful http://stackoverflow.com/questions/5852237/question-on-c-recursion-and-local-variables/5852254#5852254
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