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POHow can I get the Regex Groups for a given Capture?
 

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  1. POHow can I get the Regex Groups for a given Capture?
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    <p>I'm parsing CSS3 selectors using a regex. For example, the selector <code>a&gt;b,c+d</code> is broken down into:</p> <pre><code> Selector: a&gt;b c+d SOSS: a b c d TypeSelector: a b c d Identifier: a b c d Combinator: &gt; + </code></pre> <p>The problem is, for example, I don't know which selector the <code>&gt;</code> combinator belongs to. The <code>Selector</code> Group has 2 captures (as shown above), each containing 1 combinator. I want to know what that combinator is for that capture.</p> <p>Groups have lists of Captures, but Captures don't have lists of Groups found in that Capture. Is there a way around this, or should I just re-parse each selector?</p> <hr> <p><strong>Edit:</strong> Each capture does give you the index of where the match occurred though... maybe I could use that information to determine what belongs to what?</p> <hr> <p>So you don't think I'm insane, the syntax is actually quite simple, using my special dict class:</p> <pre><code>var flex = new FlexDict { {"GOS"/*Group of Selectors*/, @"^\s*{Selector}(\s*,\s*{Selector})*\s*$"}, {"Selector", @"{SOSS}(\s*{Combinator}\s*{SOSS})*{PseudoElement}?"}, {"SOSS"/*Sequence of Simple Selectors*/, @"({TypeSelector}|{UniversalSelector}){SimpleSelector}*|{SimpleSelector}+"}, {"SimpleSelector", @"{AttributeSelector}|{ClassSelector}|{IDSelector}|{PseudoSelector}"}, {"TypeSelector", @"{Identifier}"}, {"UniversalSelector", @"\*"}, {"AttributeSelector", @"\[\s*{Identifier}(\s*{ComparisonOperator}\s*{AttributeValue})?\s*\]"}, {"ClassSelector", @"\.{Identifier}"}, {"IDSelector", @"#{Identifier}"}, {"PseudoSelector", @":{Identifier}{PseudoArgs}?"}, {"PseudoElement", @"::{Identifier}"}, {"PseudoArgs", @"\([^)]*\)"}, {"ComparisonOperator", @"[~^$*|]?="}, {"Combinator", @"[ &gt;+~]"}, {"Identifier", @"-?[a-zA-Z\u00A0-\uFFFF_][a-zA-Z\u00A0-\uFFFF_0-9-]*"}, {"AttributeValue", @"{Identifier}|{String}"}, {"String", @""".*?(?&lt;!\\)""|'.*?(?&lt;!\\)'"}, }; </code></pre>
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    1. COHow is `a>b>c+d` broken down?
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    2. CO@BoltClock: See update.
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    3. CONow I remember to upvote your question (as well as your previous one).
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