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POHow best to make "accessable" File I/O Stream constructors (channel & ByteBuffer also)
 

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  1. POHow best to make "accessable" File I/O Stream constructors (channel & ByteBuffer also)
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    <p>I'd like to know how best to make "accessable" or "visible" a set of File I/O Stream constructors defined in my main routine, to sub-routines. </p> <p>I found that I cannot use "public", the compiler issues an "Illegal Expression" error msg. </p> <p>When I place the file I/O stream and channel constructors in the public class defined for the entire program "package". The compiler issues an error stating there's no FileNotFound or IOException handling declared, so I put on my mainline routine the following:</p> <pre><code>public static void main(String args[]) throws FileNotFoundException, IOException { // and if I then place the File I/O contructors after this: //Connect to the LU62XC Message File FileOutputStream MesgOut = new FileOutputStream(Mesg_File) ; FileChannel MesgChnl = MesgOut.getChannel() ; ByteBuffer Mesg_Bufr = ByteBuffer.allocate(128) ; //Connect to the Request Input File FileInputStream RqstInp = new FileInputStream(Rqst_File) ; //Connect to the Response Output File FileOutputStream RespOut = new FileOutputStream(Resp_File) ; //Connect to the Request/Response Log File FileOutputStream LogrOut = new FileOutputStream(Logr_File) ; </code></pre> <p>I resolve the "no exception handling error", but now my problem is the sub-routines that reference the "constructed" file objects essentianlly can't .. I get a bunch of "symbol not found" error messages. Again, if I put "public" in front of the file I/O constructors, I get the Illegal expression message. </p> <p>Is there any way out of this ??? </p> <p>Why the java compiler insists on the program handling file-not-found errors is beyond me. I mean there's already the if <code>file_object.exists()</code> method... </p> <p>IF the file's NOT there.. the OS will let you know. All ANY application program(OOP or otherwise) does when it comes to I/O of any kind is to make a request to the underlying OS. </p>
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