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5795666
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0
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2011-04-26T19:51:18.610
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2011-04-26T19:57:32.787
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2011-04-26T19:57:32.787
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5793523
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2
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There are two answers to this question. One of them is pretty straightforward (and assumes that you know the number of columns and rows of the input file in question). <pre><code>for (int a=0; a<NUMROW; a++) for (int b=0; b<NUMCOL; b++) cin>>TWODARRAY[a][b]; </code></pre> So that was pretty easy. For a variable length of data input, the long and ungainly answer I came up with is a bit more exciting. Still, I've tested it, and it works. Hope everyone's comfortable with pointers to pointers and stringstreams. <pre><code>string in; int** twoDArray=NULL; int numRow=0; int numCol=0; string** inputHold=NULL; int inputSize=10; //Since we're using pointers instead of vectors, //we have to keep track of the end of the array. inputHold=new string*[inputSize]; while (getline(cin,in)){ //The string in now contains a line of input. if (numRow==0) //Assuming that the number of inputs per column is the same in each row, //we can save on computation by only checking the number of columns once. //Performance may be improved here- it might be more efficient to use str.find for (string::iterator iter=in.begin(); iter!=in.end(); iter++){ if (*iter==' ') numCol++; } //Store the string inputHold[numRow]=new string(in); numRow++; if (numRow==inputSize) { //If we're at the end of the array, we create a bigger one and repopulate the data. string** tmpInput=inputHold; int oldsize=inputSize; inputSize=inputSize*2; inputHold=new string*[inputSize]; for (int i=0; i<oldsize; i++){ inputHold[i]=tmpInput[i]; } } } //The method that I used to determine the number of columns is mildly flawed- //it doesn't account for the end of line. So, we increment the counter. numCol=numCol+1; twoDArray=new int*[numRow]; for (int a=0; a<numRow; a++) twoDArray[a]=new int[numCol]; for (int a=0; a<numRow; a++){ istringstream parser(*(inputHold[a])); for (int b=0; b<numCol; b++){ parser>>twoDArray[a][b]; } } for (int a=0; a<numRow; a++) for (int b=0; b<numCol; b++) cout<<twoDArray[a][b]<<endl; </code></pre> Anyone got anything less complicated?
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1. USChaosphere2112
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