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    <p>While all these answers are relevant, I will try to explain what came to an expectation, that something like <em><code>delete[][] array;</code></em> may work on dynamically allocated arrays and why it's not possible:</p> <p>The syntax <code>int array[ROWS][COLS];</code> allowed on <strong>statically</strong> allocated arrays is just abstraction for programmers, which in reality creates one-dimensional array <code>int array[ROWS*COLS];</code>. But during compilation process (when dimension sizes <code>COLS</code> and <code>ROWS</code> must be constants by standard) the compiler also remembers the size of those dimensions, that are necessary to later address elements using syntax e.g. <code>array[x][y] = 45</code>. Compiler, being known of this size, will then replace <code>[x][y]</code> with the corresponding index to one-dimensional array using simple math: <code>[COLS*x + y]</code>.</p> <p>On the other hand, this is not the case with <strong>dynamically</strong> allocated arrays, if you want the same multi-dimensional functionality (in fact notation). As their size can be determined during runtime, they would have to remember the size of each additional dimension for later usage as well - and remember that for the whole life of the array. Moreover, system changes would have to be implemented here to work with arrays actually as multi-dimensional, leaving the form of <code>[x][y]</code> access notation in the code, not replacing it with an one-dimensional notation during compilation, but later replacing it within runtime.</p> <p>Therefore an <strong>absence</strong> of <em><code>array = new int[ROWS][COLS]</code></em> implies no necessity for <em><code>delete[][] array;</code></em>. And as already mentioned, it can't be used on your example to delete your "multi-dimensional" array, because your sub-arrays (additional dimensions) are allocated separately (using separate <code>new</code> call), so they are independent of the top array (<code>array_2D</code>) which contains them and they all can't be deleted at once.</p>
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