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  1. PO
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    <p>A condition (A OR NOT A) can be omited. So symbols can savely been ignored. </p> <pre><code>for (String word : "10 10-10 open-office 10B A10 UCS5000 code DV-3000 300-BR".split (" ")) if (word.matches ("(.*[A-Za-z].*[0-9])|(.*[0-9].*[A-Za-z].*)")) // do something </code></pre> <p>You didn't mention -x4, 4x-, 4-x-, -4-x or -4-x-, I expect them all to match.</p> <p>My expression looks just for something-alpha-something-digits-something, where something might be alpha, digits or symbols, and the opposite: something-alpha-something-digits-something. If something else might occur, like !#$~()[]{} and so on, it would get longer. </p> <p>Tested with scala:</p> <pre><code>scala&gt; for (word &lt;- "10 10-10 open-office 10B A10 UCS5000 code DV-3000 300-BR".split (" ") | if word.matches ("(.*[A-Za-z].*[0-9])|(.*[0-9].*[A-Za-z].*)")) yield word res89: Array[java.lang.String] = Array(10B, A10, UCS5000, DV-3000, 300-BR) </code></pre> <p>Slightly modified to filter matches: </p> <pre><code>String s = "A35, 35A, B53X, 1AC5, AB-10, 10-AB, A10-BA, BA-A10, etc. -4x, 4x- -4-x- 10-10, oe-oe, etc"; Pattern pattern = java.util.regex.Pattern.compile ("\\b([^ ,]*[A-Za-z][^ ,]*[0-9])[^ ,]*|([^ ,]*[0-9][^ ,]*[A-Za-z][^ ,]*)\\b"); matcher = pattern.matcher (s); while (matcher.find ()) { System.out.print (matcher.group () + "|") } </code></pre> <p>But I still have an error, which I don't find: </p> <pre><code>A35|35A|B53X|1AC5|AB-10|10-AB|A10-BA|BA-A10|-4x|4x|-4-x| </code></pre> <p>4x should be 4x-, and -4-x should be -4-x-. </p>
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    1. PORegex to find words with letters and numbers separated or not by symbols
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    1. USuser unknown
    1. USuser unknown
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    1. COIt's an interesting solution, but i can't split the original string by spaces (it's a rule of the solution that i'm developing). Thanks!
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      1. USFabio Thomaz
    2. COThe splitting is just to test the example. You asked for `matching words`, not `extracting matching words`.
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      1. USuser unknown
 

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