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    <pre><code>for (Transaction* transaction in transactions) { //do stuff here, or just print the object with something like the code below NSLog(@"Transaction: %@", transaction); } </code></pre> <p>Of course, when you have code like this:</p> <pre><code>[aTransaction createTransaction:n*100 ofType:credit]; [transactions addObject:aTransaction]; </code></pre> <p>...you are not actually storing the newly created transaction in the array. You are just storing the variable <code>aTransaction</code> multiple times. You may have better luck with something like:</p> <pre><code>Transaction* nextTransaction = [aTransaction createTransaction:n*100 ofType:credit]; [transactions addObject:nextTransaction]; </code></pre> <p><strong>Edit:</strong></p> <p>You may have more luck with:</p> <pre><code>#import &lt;Foundation/Foundation.h&gt; #import "BudObj.h" #import "Transaction.h" int main(int argc, char *argv[]) { Budget* europeBudget=[[Budget alloc] init]; NSMutableArray *transactions=[[NSMutableArray alloc] initWithCapacity:10]; [europeBudget createBudget:1000.00 withExchangeRate:1.2500]; Transaction* aTransaction = nil; for(int n=1;n&lt;2;n++){ //this adds 1 transaction to the array aTransaction = [[[Transaction alloc] init] autorelease]; [aTransaction createTransaction:n*100 ofType:cash]; [transactions addObject:aTransaction]; } int n=1; while (n&lt;3) { //this adds 2 transactions to the array aTransaction = [[[Transaction alloc] init] autorelease]; [aTransaction createTransaction:n*100 ofType:credit]; [transactions addObject:aTransaction]; n++; } do{ //this adds 1 transaction to the array aTransaction = [[[Transaction alloc] init] autorelease]; [aTransaction createTransaction:n*100 ofType:cash]; [transactions addObject:aTransaction]; n++; }while (n&lt;=3); //there should be 4 elements in the array now NSLog(@"\nNumber of elements in an array:%i",[transactions count]); int c; c=[transactions count]; NSLog(@"\nThe Elements are:\n"); for(int i=0;i&lt;c;i++){ Transaction* trans = [transactions objectAtIndex:i]; NSLog(@"Transaction %d: %@; type=%d, amount=%f", i, trans, [trans returnType], [trans returnAmount]); } for(Transaction *aaTransaction in transactions){ switch ([aTransaction returnType]) { case cash: [europeBudget spendDollars:[aaTransaction returnAmount]]; break; case credit: [europeBudget changeForeignCurrency:[aaTransaction returnAmount]]; break; default: break; } } [transactions release]; [europeBudget release]; return 0; } </code></pre> <p>The address that you see in your output doesn't mean that the program couldn't find the <code>Transaction</code> in the array. In fact, it means the exact opposite. The address is the address in memory of your <code>Transaction</code> instance. The reason it gets printed as an address is because that is the default behavior when printing an <code>NSObject</code> instance. Your class is not overriding this default behavior, so you get the memory address when you print it. </p> <p>If you want to override this default behavior, you can do something like:</p> <pre><code>#import "Transaction.h" @implementation Transaction //override the 'description' method to change how your object prints -(NSString*)description { NSString* friendlyType = theType == cash ? @"cash" : @"credit"; return [NSString stringWithFormat:@"Transaction: type=%@, amount=%f", friendlyType, amount]; } -(void)createTransaction:(double)theAmount ofType:(transactionType)theType{ type=theType; amount=theAmount; } -(double)returnAmount{ return amount; } -(transactionType)returnType{ return type; } @end </code></pre>
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    1. POHow to retrieve and view the elements from the NSMutableArray
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    1. COI tried this also.I'm getting some address printed out as output.
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    2. CO@Beata Jane - that is probably the address of your object instances. If you provide some details about what fields/properties exist on a `Transaction` object we can provide some better examples of how to print them in a meaningful way.
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    3. CO@aroth-I have edited the code and have given the full program above.please go through it.
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