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2011-04-13T02:29:35.220
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2013-09-21T00:16:46.720
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I've got another solution: <a href="http://splinter.com.au/build-a-url-query-string-in-obj-c-from-a-dict" rel="nofollow">http://splinter.com.au/build-a-url-query-string-in-obj-c-from-a-dict</a> <pre><code>+(NSString*)urlEscape:(NSString *)unencodedString { NSString *s = (NSString *)CFURLCreateStringByAddingPercentEscapes(NULL, (CFStringRef)unencodedString, NULL, (CFStringRef)@"!*'\"();:@&=+$,/?%#[]% ", kCFStringEncodingUTF8); return [s autorelease]; // Due to the 'create rule' we own the above and must autorelease it } // Put a query string onto the end of a url +(NSString*)addQueryStringToUrl:(NSString *)url params:(NSDictionary *)params { NSMutableString *urlWithQuerystring = [[[NSMutableString alloc] initWithString:url] autorelease]; // Convert the params into a query string if (params) { for(id key in params) { NSString *sKey = [key description]; NSString *sVal = [[params objectForKey:key] description]; // Do we need to add ?k=v or &k=v ? if ([urlWithQuerystring rangeOfString:@"?"].location==NSNotFound) { [urlWithQuerystring appendFormat:@"?%@=%@", [Http urlEscape:sKey], [Http urlEscape:sVal]]; } else { [urlWithQuerystring appendFormat:@"&%@=%@", [Http urlEscape:sKey], [Http urlEscape:sVal]]; } } } return urlWithQuerystring; } </code></pre> You can then use it like so: <pre><code>NSDictionary *params = @{@"username":@"jim", @"password":@"abc123"}; NSString *urlWithQuerystring = [self addQueryStringToUrl:@"https://myapp.com/login" params:params]; </code></pre>
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1. POCreating URL query parameters from NSDictionary objects in ObjectiveC
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1. COPlease post relevant code in your answer, that link may not be around forever.
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Querying!

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