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    <p>It looks like you want something similar to this:</p> <pre><code>#include &lt;iostream&gt; using namespace std; int main() { int standard, count1, count2, count3, count4, count5; // Initialize your int's standard = count1 = count2 = count3 = count4 = count5 = 0; do { cout&lt;&lt; "Enter value: "; cin &gt;&gt; standard; // Switch through your cases switch(standard) { case 1: count1++; break; case 2: count2++; break; case 3: count3++; break; case 4: count4++; break; case 5: count5++; break; } } while(standard != 0); // Do this type of loop for all your count vars for(int i=0;i&lt;count1;++i) cout&lt;&lt; "1"; for(int i=0;i&lt;count2;++i) cout&lt;&lt; "2"; // And so on... return 0; } </code></pre> <p>For the for loops, note that you are going from 0 to <code>&lt;</code> the total number. If you went to <code>&lt;=</code> you would go passed that number. The range <code>[0,4]</code> = 5 (or in our case <code>[0,5)</code> for the set of integers) and so does <code>[1,5]</code> so remember to mind your offsets. Good luck!</p> <p><strong>EDIT:</strong> Also recognize that the position of the <code>switch</code> statement has been moved. By placing it in the loop, you actually count every time it runs through the loop. For instance, the loop "blocks" (in other words, it waits for input) at your <code>cin</code> line. When it receives an input (though you have no error-checking, so a non-int value may cause a segfault), it will then check it against the switch statement and increment accordingly.</p> <p>By placing the <code>switch</code> statement outside the loop (as you initially had it), please realize that nothing happens. You have no <code>default</code> condition in your <code>switch</code> statement, nor a case for handling <code>0</code>. If you check your <code>switch</code> after the loop, <code>standard == 0</code> since that is how you exited the loop in the first place (therefore, standard's last value will be retained).</p> <p>Furthermore, revisit the for loop syntax. This can be done in several ways, there are many good articles here on SO which can help you further by using the search function, but it basically works like this:</p> <pre><code>for(STARTING_POINT;SOME_CONDITION;SOME_CHANGE); </code></pre> <p>STARTING_POINT = The value where you should start your loop SOME_CONDITION = When this condition is true, then the loop will terminate SOME_CHANGE = how to change your variable (i.e. from starting point) until it reaches the condition</p> <p>So a loop which looks like this:</p> <pre><code>for(int i=1;i&lt;=5;++i){ ... } </code></pre> <p>means to initialize <code>int i</code> to value <code>1</code> Until <code>i &lt;= 5</code> run through your loop Then, on every iteration, increment <code>i</code> by one (which is <code>++i</code> or <code>i++</code>)</p> <p>Finally, as you can see, I added an initialization line to my int's. What this does is it gives your variables some starting value rather than garbage value.</p> <p>I hope this helps</p> <p>Regards,<br /> Dennis M.</p>
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    1. POC++ switch statement count output
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    1. CO-1 for lots of code and little explanation.
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    2. CO@Potatoswatter: There is not much else to explain. I explained the ranges on the for loop which is where he was having the most issues it seemed to me. Looking at his original code, perhaps I can disect the for loop further, but that's all there is. This is basically the "Hello World" of loops (disregarding I/O, but this is, again, very basic since he seemingly understands it). He is not overloading the `++` operator so it is still increment as well. Please elaborate if you would like to see further explanation on this code.
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    3. COYou fundamentally changed the functionality and said "it looks like this is what you want." Clearly he's still at the "Hello, world" level and he won't be helped by having homework done for him. Even if it seems very basic to us, that is the level of instruction he needs.
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