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    <p><code>*args</code> just means that you can pass unlimited number of arguments. So this method needs 2 arguments first (builder &amp; attribute) and then you could pass any number of args after that. Here is a description of what is going on in the method relating to the args:</p> <ol> <li><p>If the third argument passed to this method is not a hash, then it sets that arg as the name and removes it (<code>args.shift</code>), otherwise use the builder name. </p></li> <li><p>Then it looks at the next arg (which would be the 4th). If its a hash, then it sets options to that arg and deletes that arg, otherwise it sets it to empty hash. </p></li> <li><p>Then it looks at the next arg (5th arg). If its a hash, then it sets that as html_options and deletes that arg, otherwise html is set to {}.</p></li> </ol> <p>Using args* can make calling the method a little cleaner (although the implementation in the method might not be). If you did not have a "name" to pass, instead of doing this:</p> <pre><code>sort_link(some_builder,some_attribute,nil,options) </code></pre> <p>you can do this:</p> <pre><code>sort_link(some_builder,some_attribute,options) </code></pre> <p>It does not force you to add a arg for name, if you don't have one.</p> <p>So for your code to work, this method would need to take options as the 4th arg, and the options hash would need to contain <code>:sort_preferences</code>. What does the code look like that is calling <code>sort_link</code>? You need to insert this option into that hash before it gets to this method.</p>
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    1. COTo answer your question, the calling code is: `= sort_link @search, :average_rating, "Best Photography", :sort_preference=>:desc`
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    2. COOk, I get it now -- I needed to move `options = args.first.is_a?(Hash) ? args.shift : {}` up in order to make my if statement work. Once that line was moved up it works. Thank you for your explanation, that helped a lot!
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