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    <p>JavaScript is parsing the group of 3 numbers as an octal number when there's a leading zero digit. When the group of three digits is all zeros, the result is the same whether the base is octal or decimal.</p> <p>But when you give JavaScript '009' (or '008'), that's an invalid octal number, so you get zero back.</p> <p>If you had gone through the whole set of numbers from 190,000,001 to 190,000,010 you'd hav seen JavaScript skip '...,008' and '...,009' but emit 'eight' for '...,010'. That's the 'Eureka!' moment.</p> <p>Change: </p> <pre><code>for (j = 0; j &lt; finlOutPut.length; j++) { finlOutPut[j] = triConvert(parseInt(finlOutPut[j])); } </code></pre> <p>to</p> <pre><code>for (j = 0; j &lt; finlOutPut.length; j++) { finlOutPut[j] = triConvert(parseInt(finlOutPut[j],10)); } </code></pre> <p>Code also kept on adding commas after every non-zero group, so I played with it and found the right spot to add the comma.</p> <p>Old:</p> <pre><code>for (b = finlOutPut.length - 1; b &gt;= 0; b--) { if (finlOutPut[b] != "dontAddBigSufix") { finlOutPut[b] = finlOutPut[b] + bigNumArry[bigScalCntr] + ' , '; bigScalCntr++; } else { //replace the string at finlOP[b] from "dontAddBigSufix" to empty String. finlOutPut[b] = ' '; bigScalCntr++; //advance the counter } } //convert The output Arry to , more printable string for(n = 0; n&lt;finlOutPut.length; n++){ output +=finlOutPut[n]; } </code></pre> <p>New:</p> <pre><code>for (b = finlOutPut.length - 1; b &gt;= 0; b--) { if (finlOutPut[b] != "dontAddBigSufix") { finlOutPut[b] = finlOutPut[b] + bigNumArry[bigScalCntr]; // &lt;&lt;&lt; bigScalCntr++; } else { //replace the string at finlOP[b] from "dontAddBigSufix" to empty String. finlOutPut[b] = ' '; bigScalCntr++; //advance the counter } } //convert The output Arry to , more printable string var nonzero = false; // &lt;&lt;&lt; for(n = 0; n&lt;finlOutPut.length; n++){ if (finlOutPut[n] != ' ') { // &lt;&lt;&lt; if (nonzero) output += ' , '; // &lt;&lt;&lt; nonzero = true; // &lt;&lt;&lt; } // &lt;&lt;&lt; output +=finlOutPut[n]; } </code></pre>
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    1. COThanks a lot!!!!! You Are my javaScript hero!!!
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    2. CO@Reid Now it's OK?
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