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    <p>sure, you can do this even with a simple JSP file... (this only works with NTLMv1, not v2, I'm still looking for that..)</p> <p>So the code for the JSP is (I've tried it on Apache Tomcat 6)</p> <pre><code>&lt;%@ page import="sun.misc.BASE64Encoder" %&gt; &lt;% String auth = request.getHeader("Authorization"); String s = ""; //no auth, request NTLM if (auth == null) { response.setStatus(response.SC_UNAUTHORIZED); response.setHeader("WWW-Authenticate", "NTLM"); return; } //check what client sent if (auth.startsWith("NTLM ")) { out.println(auth); byte[] msg = new sun.misc.BASE64Decoder().decodeBuffer(auth.substring(5)); int off = 0, length, offset; out.println("&lt;br&gt;"+msg); out.println("&lt;br&gt;"+msg[1]+" "+msg[2]+" "+msg[3]+" "+msg[4]+" "+msg[5]+" "+msg[6]+" "+msg[7]+" "+msg[8]+" "+msg[9]+" "+msg[10]+"&lt;br&gt;"); if (msg[8] == 1) { off = 18; byte z = 0; byte[] msg1 = {(byte)'N', (byte)'T', (byte)'L', (byte)'M', (byte)'S',(byte)'S', (byte)'P', z,(byte)2, z, z, z, z, z, z, z, (byte)40, z, z, z, (byte)1, (byte)130, z, z, z, (byte)2, (byte)2, (byte)2, z, z, z, z, // z, z, z, z, z, z, z, z}; // send ntlm type2 msg response.setStatus(response.SC_UNAUTHORIZED); response.setHeader("WWW-Authenticate", "NTLM " + new sun.misc.BASE64Encoder().encodeBuffer(msg1).trim()); return; } else if (msg[8] == 3) { off = 30; length = msg[off+17]*256 + msg[off+16]; offset = msg[off+19]*256 + msg[off+8]; s = new String(msg, offset, length); // print computer name // out.println(s + " "); } else return; length = msg[off+1]*256 + msg[off]; offset = msg[off+3]*256 + msg[off+2]; s = new String(msg, offset, length); //domain//out.println(s + " "); length = msg[off+9]*256 + msg[off+8]; offset = msg[off+11]*256 + msg[off+10]; s = new String(msg, offset, length); out.println("Hello &lt;span style='position:relative; width:190;" + " height:10;filter:glow(Color=#009966,Strength=1)'&gt;"); out.println(s + "&lt;/SPAN&gt;"); } %&gt; </code></pre>
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    1. POget username from NTLM auth header?
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    1. USPeter
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    1. COWhy does msg[8] == 1 mean they are unauthorised?
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      1. USPaul Hutchinson
 

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