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POSingle Instance Application - Passing commands
 

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  1. POSingle Instance Application - Passing commands
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    <p>I'm using wxPython, and I'm trying to make a single instance application. As far as this goes, there is no problem. My problem is passing commands to the already existing instance.<br> So lets say that when I double click a file that is associated with my application, it reads the file and displays, here is an example:</p> <pre><code>import wx import sys import os import SocketServer import socket import threading class MyFrame(wx.Frame): def __init__(self, parent, id, title): wx.Frame.__init__(self, parent, id, title, wx.DefaultPosition, wx.Size(320, 350)) getfile = os.path.abspath(sys.argv[1]) print getfile fopen = open (getfile, 'r') fread = fopen.read() panel = wx.Panel(self, -1) wx.StaticText(panel, -1, fread, (45, 25), style=wx.ALIGN_CENTRE) self.Centre() class ThreadedTCPRequestHandler(SocketServer.BaseRequestHandler): def handle(self): data = self.request.recv(1024) cur_thread = threading.currentThread() # do something with the request print "work" # could instead of the length of the input, could return error codes, more # information (if the request was a query), etc. Using a length function # as a simple example response = 'string length: %d' % len(data) print 'responding to',data,'with',response self.request.send(response) class ThreadedTCPServer(SocketServer.ThreadingMixIn, SocketServer.TCPServer): stopped = False allow_reuse_address = True def serve_forever(self): while not self.stopped: self.handle_request() def force_stop(self): self.server_close() self.stopped = True def client(ip, port, message): sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) sock.connect((ip, port)) sock.send(message) response = sock.recv(1024) print "Received: %s" % response sock.close() def start_server(host, port): server = ThreadedTCPServer((host, port), ThreadedTCPRequestHandler) ip, port = server.server_address # Start a thread with the server -- that thread will then start one # more thread for each request server_thread = threading.Thread(target=server.serve_forever) # Exit the server thread when the main thread terminates server_thread.setDaemon(True) server_thread.start() return server class MyApp(wx.App): def OnInit(self): frame = MyFrame(None, -1, 'test') frame.Show(True) self.SetTopWindow(frame) return True def main(): app = MyApp(0) app.MainLoop() if __name__ == '__main__': HOST, PORT = socket.gethostname(), 61955 server = None try: client(HOST, PORT, ' '.join(sys.argv)) sys.exit() except socket.error: server = start_server(HOST, PORT) main() </code></pre> <p>This works just fine, but now I want to make it a single instance application. And I know that there are several ways to accomplish this, and in my case, I found that listening to a defined port is probably the best option. But even using such option, I have no idea on how I could pass the information of the file or, atleast, the name to the original instance and display it.</p> <p>So the application should be:</p> <ul> <li>A single instance application.</li> <li>It should be able to read the double-clicked files.</li> <li>If an instance is already open, then pass the information or file name to the original instance so it can refresh and display the file's data automatically.</li> </ul> <p>Also, I didn't include any code for listening to a defined port because I really don't know much about it, so any help on this subject is also greatly appreciated.</p> <p><strong>EDIT:</strong> Code edited with "listening to a defined port", it is taken from an example. Note that <code>print "work"</code> does send to the running instance, I just don't know how to make it work in my occasion (because of my plain ignorance).</p>
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    1. CO"plain ignorance"? Of what? Please be specific on what's not working. You have a bunch of requirements -- what **specific** question or problem or error are you getting?
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    2. CONever mind, I figured it out, I'll probably post the answer soon, but it was quite easy. Thanks anyway.
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    3. COCare to share your solution with us?
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