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    <p>The quick and dirty version: <code>df $file | awk 'NR == 2 {print $1}'</code>.</p> <p>Programmatically... well, there's a reason I started with the quick and dirty version. There's no portable way to programmatically get the list of mounted filesystems. (<code>getmntent()</code> gets <code>fstab</code> entries, which is not the same thing.) Moreover, you can't even parse the output of <code>mount(8)</code> reliably; on different Unixes, the mountpoint may be the first or the last item. The most portable way to do this ends up being... parsing <code>df</code> output (And even that is iffy, as you noticed with the partition number.). So you're right back to the quick and dirty shell solution anyway, unless you want to traverse <code>/dev</code> and look for block devices with matching <code>major(st_rdev)</code> (<code>major()</code> being from <code>sys/types.h</code>).</p> <p>If you restrict this to Linux, you can use <code>/proc/mounts</code> to get the list of mounted filesystems. Other specific Unixes can similarly be optimized: for example, on OS X and I think FreeBSD, you can use <code>sysctl()</code> on the <code>vfs</code> tree to get mountpoints. At worst you can find and use the appropriate header file to decipher whatever the mount table file is (and yes, even that varies: on Solaris it's <code>/etc/mnttab</code>, on many other systems it's <code>/etc/mtab</code>, some systems put it in <code>/var/run</code> instead of <code>/etc</code>, and on many Linuxes it's either nonexistent or a symlink to <code>/proc/mounts</code>). And its format is different on pretty much every Unix-like OS.</p>
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    1. COThanks, but I would like to achive this using only system/library calls. Also, your suggestion is giving me the partition number ;-)
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    2. CO@Grieih: +1 to this because you never specified you wanted this in C-code. P.S. adding `-F'[0-9]'` will remove the partition number
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    3. CO@Greih: see update. I went with that for a reason, unfortunately.
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