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  1. PO
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    <p>1) If what is meant by mapping 01-24 to 00-23 is that 01 is mapped to 00, 02 is mapped to 01, etc. then here is a solution; otherwise see 2) below.</p> <p>The <code>gsubfn</code> function in the gsubfn package can pick out strings and apply a function to them replacing the match with the output of the function. We read the Lines in and then match a space, two characters and a colon replacing the two characters with a number one less. Finally we re-read it:</p> <pre><code>library(gsubfn) L &lt;- readLines(textConnection(Lines)) L2 &lt;- gsubfn(" (..):", ~ sprintf(" %02d:", as.numeric(..1)-1), L) DF &lt;- read.csv(textConnection(L2), as.is = TRUE) DF$Date &lt;- as.POSIXct(DF$Date, format = "%m/%d %H:%M:%S") </code></pre> <p>Thus the last bit of the result is:</p> <pre><code>&gt; tail(DF) Date Outdoor Indoor 21 01/01 20:00:00 25.9 21.1 22 01/01 21:00:00 25.8 21.3 23 01/01 22:00:00 25.6 21.4 24 01/01 23:00:00 25.5 21.5 25 01/02 00:00:00 25.4 21.6 26 01/02 01:00:00 25.3 21.8 </code></pre> <p>2) If what is meant by mapping 01-24 to 00-23 is that 01-23 get mapped to themelves and 24 gets mapped to 00 of the next day then calculate <code>DF</code> as shown above and then do this:</p> <pre><code>DF$Date &lt;- DF$Date + 3600 </code></pre> <p>so that the last bit of the result is:</p> <pre><code>&gt; tail(DF) Date Outdoor Indoor 21 2011-01-01 21:00:00 25.9 21.1 22 2011-01-01 22:00:00 25.8 21.3 23 2011-01-01 23:00:00 25.6 21.4 24 2011-01-02 00:00:00 25.5 21.5 25 2011-01-02 01:00:00 25.4 21.6 26 2011-01-02 02:00:00 25.3 21.8 </code></pre>
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    1. POHow to change the hours in a dataset from 01-24 to 00-23 in R?
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    1. USG. Grothendieck
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    1. COThis doesn't work, as it substracts 1 from _all_ times. That is not the point, your output is not consistent with the original frame.
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      1. USJoris Meys
    2. CO@J, If that is what is meant then I have added a second answer which is the same as the first except for the last line.
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