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    <p>You might also consider using <code>collections.counter</code> if you are using Python >=2.7</p> <p><a href="http://docs.python.org/library/collections.html#collections.Counter" rel="nofollow noreferrer">http://docs.python.org/library/collections.html#collections.Counter</a></p> <p>It adds a number of methods like 'most_common', which might be useful in this type of application.</p> <p>From Doug Hellmann's PyMOTW:</p> <pre><code>import collections c = collections.Counter() with open('/usr/share/dict/words', 'rt') as f: for line in f: c.update(line.rstrip().lower()) print 'Most common:' for letter, count in c.most_common(3): print '%s: %7d' % (letter, count) </code></pre> <p><a href="http://www.doughellmann.com/PyMOTW/collections/counter.html" rel="nofollow noreferrer">http://www.doughellmann.com/PyMOTW/collections/counter.html</a> -- although this does letter counts instead of word counts. In the <code>c.update</code> line, you would want to replace <code>line.rstrip().lower</code> with <code>line.split()</code> and perhaps some code to get rid of punctuation.</p> <p><strong>Edit:</strong> To remove punctuation here is probably the fastest solution:</p> <pre><code>import collections import string c = collections.Counter() with open('DataSO.txt', 'rt') as f: for line in f: c.update(line.translate(string.maketrans("",""), string.punctuation).split()) </code></pre> <p>(borrowed from the following question <a href="https://stackoverflow.com/questions/265960/best-way-to-strip-punctuation-from-a-string-in-python">Best way to strip punctuation from a string in Python</a>)</p>
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    1. COreally great! tnx
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