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POcv::Mat_ to std::vector conversion
 

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  1. POcv::Mat_ to std::vector conversion
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    <p>I use OpenCV 2.0, there is a method in the <code>cv::Mat_&lt;_Tp&gt;</code> class:</p> <pre><code>// conversion to vector. operator vector&lt;_Tp&gt;() const; </code></pre> <p>When instantiated, the implementation does not compile on MSVS 2005:</p> <pre><code>template&lt;typename _Tp&gt; inline Mat_&lt;_Tp&gt;::operator vector&lt;_Tp&gt;() const { CV_Assert( rows == 1 || cols == 1 ); return isContinuous() ? vector&lt;_Tp&gt;((size_t)(rows + cols - 1), (_Tp*)data) : (vector&lt;_Tp&gt;)((Mat_&lt;_Tp&gt;)this-&gt;t()); } </code></pre> <p>Is it a new fancy constructor of <code>std::vector</code> that takes <code>size_t</code> and <code>_Tp*</code> from TR1 or something?</p> <p>I thought they could just initialize the vector by an iterator instead:</p> <pre><code>vector&lt;_Tp&gt;((_Tp*)data, (_Tp*)data + rows + cols - 1) </code></pre> <p>Is it a bug, or don't I know something?</p> <p><p></p> <p>UPD. Compiler error text: </p> <pre><code>...\lib\opencv\include\opencv\cxmat.hpp(691) : error C2665: 'std::vector&lt;_Ty&gt;::vector' : none of the 6 overloads could convert all the argument types with [ _Ty=double ] c:\program files\microsoft visual studio 8\vc\include\vector(473): could be 'std::vector&lt;_Ty&gt;::vector(__w64 unsigned int,const _Ty &amp;)' with [ _Ty=double ] while trying to match the argument list '(size_t, double *)' ...\lib\opencv\include\opencv\cxmat.hpp(689) : while compiling class template member function 'cv::Mat_&lt;_Tp&gt;::operator std::vector&lt;_Ty&gt;(void) const' with [ _Tp=double, _Ty=double ] z:\dev\mine\temp\temp\entry.cpp(37) : see reference to class template instantiation 'cv::Mat_&lt;_Tp&gt;' being compiled with [ _Tp=double ] </code></pre>
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    1. USRoman Shapovalov
    1. USRoman Shapovalov
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    1. COCan you post the compiler error you are getting?
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      1. USBjörn Pollex
    2. CO@Space_C0wb0y I've added it, but I doubt it can help. The message just says there is no suitable overload.
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      1. USRoman Shapovalov
 

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