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    <pre><code>f = Sin[t]; plot = Plot[f, {t, 0, 10}] </code></pre> <p>One way to extract points is as follows:</p> <pre><code>points = Cases[ Cases[InputForm[plot], Line[___], Infinity], {_?NumericQ, _?NumericQ}, Infinity]; </code></pre> <p>ListPlot to 'take a look'</p> <pre><code>ListPlot[points] </code></pre> <p>giving the following:</p> <p><img src="https://i.stack.imgur.com/E2dMx.gif" alt="enter image description here"></p> <p><strong>EDIT</strong> Brett Champion has pointed out that <code>InputForm</code> is superfluous. </p> <pre><code>ListPlot@Cases[ Cases[plot, Line[___], Infinity], {_?NumericQ, _?NumericQ}, Infinity] </code></pre> <p>will work. </p> <p>It is also possible to paste in the plot graphic, and this is sometimes useful. If,say, I create a ListPlot of external data and then mislay the data file (so that I only have access to the generated graphic), I may regenerate the data by selecting the graphic cell bracket,copy and paste:</p> <pre><code>ListPlot@Transpose[{Range[10], 4 Range[10]}] points = Cases[ Cases[** Paste_Grphic _Here **, Point[___], Infinity], {_?NumericQ, _?NumericQ}, Infinity] </code></pre> <p><strong>Edit 2</strong>.</p> <p>I should also have cross-referenced and acknowledged <a href="https://stackoverflow.com/questions/4245946/vertexcoordinate-rules-and-vertexlist-from-graphplot-graphic/4250069#4250069">this</a> very nice answer by Yaroslav Bulatov. </p> <p><strong>Edit 3</strong></p> <p>Brett Champion has not only pointed out that <code>FullForm</code> is superfluous, but that in cases where a <code>GraphicsComplex</code> is generated, applying <code>Normal</code> will convert the complex into primitives. This can be very useful. </p> <p>For example:</p> <pre><code>lp = ListPlot[Transpose[{Range[10], Range[10]}], Filling -&gt; Bottom]; Cases[ Cases[Normal@lp, Point[___], Infinity], {_?NumericQ, _?NumericQ}, Infinity] </code></pre> <p>gives (correctly)</p> <blockquote> <p>{{1., 1.}, {2., 2.}, {3., 3.}, {4., 4.}, {5., 5.}, {6., 6.}, {7., 7.}, {8., 8.}, {9., 9.}, {10., 10.}}</p> </blockquote> <p>Thanks to Brett Champion.</p> <p>Finally, a neater way of using the general approach given in this answer, which I found <a href="http://mathgis.blogspot.com/2008/08/how-to-extract-points-from-plot.html" rel="nofollow noreferrer">here</a></p> <p>The OP problem, in terms of a ListPlot, may be obtained as follows:</p> <pre><code>ListPlot@Cases[g, x_Line :&gt; First@x, Infinity] </code></pre> <p><strong>Edit 4</strong></p> <p>Even simpler </p> <pre><code>ListPlot@Cases[plot, Line[{x__}] -&gt; x, Infinity] </code></pre> <p>or</p> <pre><code>ListPlot@Cases[** Paste_Grphic _Here **, Line[{x__}] -&gt; x, Infinity] </code></pre> <p>or</p> <pre><code>ListPlot@plot[[1, 1, 3, 2, 1]] </code></pre> <p>This evaluates to <code>True</code></p> <pre><code>plot[[1, 1, 3, 2, 1]] == Cases[plot, Line[{x__}] -&gt; x, Infinity] </code></pre>
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    1. CO`InputForm` is unnecessary, but you might replace it with `Normal` if you don't have control over where the plot is coming from. If you add a Filling option, for example, the plot will contain `GraphicsComcplex` and the points will just be integer references to the global set of points.
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    2. CO@Brett Champion Thanks! I never realized that `InputForm` was superfluous. I have edited accordingly. I usually 'take a look' before data extraction. ( Usually a strategy then suggests itself.) Can you post an example where GraphicsComplex will give integer refs? `f = Sin[t]; plotfill = Plot[f, {t, 0, 10}, Filling -> Axis]; ListPlot@Cases[ Cases[plot, GraphicsComplex[___], Infinity], {_?NumericQ, _?NumericQ}, Infinity]` will work, for example. Thanks for your comment. I use this approach quite a bit.
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    3. CO`ListPlot[{1, 2}, Filling -> Bottom]` contains the following GraphicsComplex: `GraphicsComplex[{{1., 1.}, {2., 2.}, {1., 0.}, {2., 0.}, {1., 1.}, {2., 2.}}, {{{}, {}, {}, {}, {Directive[{Opacity[0.2], Hue[0.67, 0.6, 0.6]}], Line[{3, 1}], Line[{4, 2}]}}, {{}, {Hue[0.67, 0.6, 0.6], Point[{5, 6}]}, {}}}]`. The `Line[{4,2}]` means that we're drawing a line from the fourth point (`{2., 0.}`) to the second point (`{2., 2.}`).
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