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2008-09-10T08:38:22.883
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2012-05-24T11:35:00
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2012-05-24T11:35:00
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aku
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<p>Here is an example:</p> <pre><code>var user1 = new User {Name = "steve", Age = 28}; var user2 = new User {Name = "foobar", Age = 28}; Expression<Func<User, bool>> expression1 = t => t.Name == "steve"; Expression<Func<User, bool>> expression2 = t => t.Age == 28; var invokedExpression = Expression.Invoke(expression2, expression1.Parameters.Cast<Expression>()); var result = Expression.Lambda<Func<User, bool>>(Expression.And(expression1.Body, invokedExpression), expression1.Parameters); Console.WriteLine(result.Compile().Invoke(user1)); // true Console.WriteLine(result.Compile().Invoke(user2)); // false </code></pre> <p>You can reuse this code via extension methods: </p> <pre><code>class User { public string Name { get; set; } public int Age { get; set; } } public static class PredicateExtensions { public static Expression<Func<T, bool>> And<T>(this Expression<Func<T, bool>> expression1,Expression<Func<T, bool>> expression2) { InvocationExpression invokedExpression = Expression.Invoke(expression2, expression1.Parameters.Cast<Expression>()); return Expression.Lambda<Func<T, bool>>(Expression.And(expression1.Body, invokedExpression), expression1.Parameters); } } class Program { static void Main(string[] args) { var user1 = new User {Name = "steve", Age = 28}; var user2 = new User {Name = "foobar", Age = 28}; Expression<Func<User, bool>> expression1 = t => t.Name == "steve"; Expression<Func<User, bool>> expression2 = t => t.Age == 28; var result = expression1.And(expression2); Console.WriteLine(result.Compile().Invoke(user1)); Console.WriteLine(result.Compile().Invoke(user2)); } } </code></pre>
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1. POHow do I compose existing Linq Expressions
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1. USDan Atkinson
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