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    <p><strong>This transformation</strong>:</p> <pre><code>&lt;xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"&gt; &lt;xsl:output method="text"/&gt; &lt;xsl:strip-space elements="*"/&gt; &lt;xsl:template match="/*"&gt; "&lt;xsl:apply-templates select="seg/text()"/&gt;" &lt;/xsl:template&gt; &lt;xsl:template match="seg/text()"&gt; &lt;xsl:value-of select= "translate(normalize-space(translate(.,'&amp;#xA;;', ';:')), ';', ' ' ) "/&gt; &lt;/xsl:template&gt; &lt;/xsl:stylesheet&gt; </code></pre> <p><strong>when applied on this XML document</strong> (combination of your case 1 ad case2):</p> <pre><code>&lt;tuv xml:lang="zh-cn" changedate="20110216T070945Z"&gt; &lt;seg&gt; &lt;ut&gt;# 302 &lt;/ut&gt;The gradient of the; objective function cannot be &lt;ph x="2" type="inldel"&gt;! &lt;/ph&gt;computed at the starting point &lt;/seg&gt; &lt;/tuv&gt; </code></pre> <p><strong>produces the wanted, correct result:</strong></p> <pre><code> "The gradient of the: objective function cannot be computed at the starting point " </code></pre> <p><strong>Explanation</strong>:</p> <ol> <li><p>In the innermost translate, in every text-node child of <code>seg</code> any ';' is replaced with ':' and any NL character is replaced with a ';'.</p></li> <li><p>1normalize-space()<code>is issued on the result of the innermost</code>translate()` and this strips off the leading and trailing white space, however the ';' characters are not touched -- this is the only reason we replaced the NL characters with ';' in step 1.</p></li> <li><p>Finally, a <code>translate()</code> replaces any ';' with a space.</p></li> </ol>
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    1. POHow to output/display modified text value using xslt
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    1. USDimitre Novatchev
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    1. CO+1 for also showing good style.
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    2. CO@Dimitre: And why not `translate(normalize-space(),';',':')`?
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    3. CObecause `normalize-space() will destroy any NL characters, and they would not then be replaced as the OP wants.
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