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POTile (scalable) stacking algorithm
 

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    <p>Here is the problem. I have rectangular canvas that have size of 1. So it have coordinate sistem of (0.0 ... 1.0 - x and 0.0 ... 1.0 - y).</p> <p>I also have some tiles. Tiles are also rectangles. They have diffrent size and amount of tiles is a variable.</p> <p>I want to <strong>stack</strong> tiles in rectangular canvas, from 0.0 to 1.0 (<strong>from left to right, from top to bottom</strong>):</p> <p>1) tiles have to fit in canvas (but fill as much space as they could)</p> <p>2) tiles have to be scaled (if they don't fit), each tile should be scaled by the same amount (they have to remain same proportions).</p> <p>3) imagine that you have this 'tiles' in your hand, and you placing them into this canvas one after another</p> <p>4) it almost like <strong>"TreeMap algorithm"</strong> but - shape of tiles have to be the same (<strong>rectangles</strong>) and <strong>i don't need to fill all space</strong> of canvas</p> <p><img src="https://i.stack.imgur.com/CJWek.png" alt="here is what i want to get"></p> <p><strong>Is there anybody who can show me an algoritm in any C alike language (C, C++, Java, C#)?</strong></p> <p>*I tried this.</p> <p>1) i calculated area of tile, then i calculate a sum of tile's areas (for example: i have two tiles, one have area of 2, other area of 1, them it's mean i have total sum of 3)</p> <p>2) then i calculate what "proportion" each tile have in "total sum of areas" (for example: 2/3 and 1/3)</p> <p>3) then calculate size of rectangle tile by Math.sqrt(x) (for example: Math.sqrt(2/3))</p> <p>4) then draw tile one by one...</p> <p>But this dosen't work always. Sometimes i get tiles to be out of canvas..*</p>
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    1. COYou don't give any criteria for optimization. One algorithm would be to line up the tiles horizontally in a single row with tops aligned, then scale the row so the tallest tile and the sum of the tile widths are <= 1.
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    2. COwell.. i will repeat my self _I want to **stack** tiles in rectangular canvas, from 0.0 to 1.0 (from left to right, from top to bottom)_
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    3. COYour example is confusing as is your description. It doesn't seem like you're stacking things at all. Maybe the word doesn't mean what you think it means. Plus, @Ted's right. Just shrink all your tiles down to an infinitesimally small proportion and then line them up. Without an optimization function, that's perfectly legit.
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