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plurals

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primarykey
Id
5205142
data
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0
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0
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0
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CreationDate
2011-03-05T16:39:50.607
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0
LastActivityDate
2011-03-05T16:39:50.607
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0
OwnerUserId
256793
ParentId
4997346
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2
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0
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0
LastEditorDisplayName
text
Body
Since there was never a real answer to this question I will summarize: <ol> <li>One Main thread which handles the sending, and spawns a receiving thread</li> <li>Block forever, exceptions are costly, so there is no need to let it time out.</li> </ol> In order to stop the thread I basically set the stop flag then terminate the underlying connection in a "terminate" message of the parent. In return which causes an exception in the child. In the exception handling block I then check the ConnectionException, if the"stop" flag has been set, I gracefully stop the receiving thread, if it was an ungraceful exit, I will then notify the parent thread. Hope this helps, this was a super annoying problem, but I am glad it is over. <pre><code>class Manager: def __init__(self): self.receiver = MessageReceiver(shutdown_hook = self.shutdown_hook) self.receiver.start() #do other stuff sending/etc... def terminate(self): self.receiver.stop() self.receiver.close() def shutdown_hook(self, t_id, child): print '%s - Unexpected thread shutdown, handle this.. restart thread?' % str(t_id)) class MessageReceiver(Thread): def __init__(self,shutdown_hook = None): Thread.__init__(self) self.receiver = Receiver() self.shutdown_hook = shutdown_hook def run(self): #stop is a flag that i use to stop the thread... while(not stopped ): try: message = self.receiver.pull() print "Message" + message except ConnectionException as e: if stopped: #we are in the process of stopping pass else: self.shutdown_hook(self.iden, e) break finally: receiver.close() </code></pre>
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1. POPython threading design question (Working with a method that blocks forever)
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1. PTAnswer
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1. USNix
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1. POPython threading design question (Working with a method that blocks forever)
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