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    <p>Javascript doesn't have "associative arrays" the way you're thinking of them. Instead, you simply have the ability to set object properties using array-like syntax (as in your example), plus the ability to iterate over an object's properties.</p> <p>The upshot of this is that there is no guarantee as to the <em>order</em> in which you iterate over the properties, so there is nothing like a sort for them. Instead, you'll need to convert your object properties into a "true" array (which does guarantee order). Here's a code snippet for converting an object into an array of two-tuples (two-element arrays), sorting it as you describe, then iterating over it:</p> <pre><code>var tuples = []; for (var key in obj) tuples.push([key, obj[key]]); tuples.sort(function(a, b) { a = a[1]; b = b[1]; return a &lt; b ? -1 : (a &gt; b ? 1 : 0); }); for (var i = 0; i &lt; tuples.length; i++) { var key = tuples[i][0]; var value = tuples[i][1]; // do something with key and value } </code></pre> <p>You may find it more natural to wrap this in a function which takes a callback:</p> <p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false"> <div class="snippet-code"> <pre class="snippet-code-js lang-js prettyprint-override"><code>function bySortedValue(obj, callback, context) { var tuples = []; for (var key in obj) tuples.push([key, obj[key]]); tuples.sort(function(a, b) { return a[1] &lt; b[1] ? 1 : a[1] &gt; b[1] ? -1 : 0 }); var length = tuples.length; while (length--) callback.call(context, tuples[length][0], tuples[length][1]); } bySortedValue({ foo: 1, bar: 7, baz: 3 }, function(key, value) { document.getElementById('res').innerHTML += `${key}: ${value}&lt;br&gt;` });</code></pre> <pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;p id='res'&gt;Result:&lt;br/&gt;&lt;br/&gt;&lt;p&gt;</code></pre> </div> </div> </p>
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    1. POHow to sort an associative array by its values in Javascript?
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    1. COThanks so much! This worked perfectly.
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      1. USJohn Smith
    2. COThe "obj" in "bySortedValue(obj" should be changed to "array" in order for the function to work properly.
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    3. CO@hakksor — Goodness, but that went a while without getting caught! Thanks for letting me know.
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