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    <p><strong>Cosmetic changes and bugfix</strong></p> <p>The regular expression <strong>must</strong> read <code>\bfunction\b</code> to avoid false positives!</p> <p>Functions defined in blocks (e.g. in the bodies of loops) will be ignored if <code>nested</code> does not evaluate to <code>true</code>.</p> <pre><code>function tokenize(code) { var code = code.split(/\\./).join(''), regex = /\bfunction\b|\(|\)|\{|\}|\/\*|\*\/|\/\/|"|'|\n|\s+/mg, tokens = [], pos = 0; for(var matches; matches = regex.exec(code); pos = regex.lastIndex) { var match = matches[0], matchStart = regex.lastIndex - match.length; if(pos &lt; matchStart) tokens.push(code.substring(pos, matchStart)); tokens.push(match); } if(pos &lt; code.length) tokens.push(code.substring(pos)); return tokens; } var separators = { '/*' : '*/', '//' : '\n', '"' : '"', '\'' : '\'' }; function extractInnerFunctionNames(func, nested) { var names = [], tokens = tokenize(func.toString()), level = 0; for(var i = 0; i &lt; tokens.length; ++i) { var token = tokens[i]; switch(token) { case '{': ++level; break; case '}': --level; break; case '/*': case '//': case '"': case '\'': var sep = separators[token]; while(++i &lt; tokens.length &amp;&amp; tokens[i] !== sep); break; case 'function': if(level === 1 || (nested &amp;&amp; level)) { while(++i &lt; tokens.length) { token = tokens[i]; if(token === '(') break; if(/^\s+$/.test(token)) continue; if(token === '/*' || token === '//') { var sep = separators[token]; while(++i &lt; tokens.length &amp;&amp; tokens[i] !== sep); continue; } names.push(token); break; } } break; } } return names; } </code></pre>
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    1. POExtracting nested function names from a JavaScript function
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    1. CO@Peter: should work now
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    2. COYep, that appears to work here now.
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    3. COThanks for this answer Christoph. I'll write some unit tests to see if it meets all scenarios. I'm also initiating a bounty to see if anyone can come up with a shorter solution.
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