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POHow to position part of the line after pattern (including it) after 80th character?
 

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  1. POHow to position part of the line after pattern (including it) after 80th character?
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    <p>I know that question sounds a little odd but i will try to explain it more.</p> <p>I have a file <code>params</code> that looks like this: </p> <pre><code>3 p 1 1.732051 0 1.9628$/x2r_a/ 4 p 1 1.732051 0 -1.9628$/x2r_a/ 5 p -1 1.732051 0 1.9628$/x2r_a/ 6 p -1 1.732051 0 -1.9628$/x2r_a/ </code></pre> <p>What i want to achieve is to move everything after (and with) <code>$</code> to the right, ie 80th 'place' of a line:</p> <pre><code>3 p 1 1.732051 0 1.9628 $/x2r_a/ 4 p 1 1.732051 0 -1.9628 $/x2r_a/ 5 p -1 1.732051 0 1.9628 $/x2r_a/ 6 p -1 1.732051 0 -1.9628 $/x2r_a/ </code></pre> <p>We don't know the exact length of the string before the <code>$</code> sign. Also the space between must be filled with spaces and nothing more.</p> <p>As always i need to do it in bash 2.05 probably with sed, awk or sth like that. </p> <p>UPDATE<br> I wasn't specific about how file look like so here's more: </p> <pre><code>c ------------------ c Something stupid c ------------------ c there is a number: 9$/ar_numb/ c a line that looks 1 px 0.9814$/r_a/ 2 px -0.9814$/r_a/ 3 p 1 1.732051 0 1.9628$/x2r_a/ 4 p 1 1.732051 0 -1.9628$/x2r_a/ 5 p -1 1.732051 0 1.9628$/x2r_a/ 6 p -1 1.732051 0 -1.9628$/x2r_a/ c c dirty line 7 cz 0.9347$/x05d_a/ c very dirty 41 p 0$/A_Nel/!jl 1$/B_Nel/!jl 0$/C_Nel/!jl 0$/D_Nel/!jl $bad element 42 p 1.723051$/A_NEel/!jl 1$/B_NEel/!jl 0$/C_NEel/!jl 0$/D_NEel/!jl $kokode nanika kaite kudasai </code></pre> <p>I will not post changed version becouse it would be too long. I want <code>$[string]</code> parts to be moved to the right, but those lines without <code>$</code> thing will remain as they are.</p>
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