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    <p>A quick, dirty, and almost-not-pseudo-code answer:</p> <pre><code>StringBuilder sb = new StringBuilder("["); Set&lt;Character&gt; metaChars = //...appropriate initialization while (sourceString.length() != 0) { char c = sourceString.charAt(0); sb.append(metaChars.contains(c) ? "\\"+c : c); sourceString.replace(c,''); } sb.append("]"); Pattern p = Pattern.compile(sb.toString()); //...can check here for the appropriate sb.length cases // e.g, 2 = empty, all chars equals the count of whatever set qualifies as all chars, etc </code></pre> <p>Which gives you the unique string of char's you want to match, with <a href="http://download.oracle.com/javase/tutorial/essential/regex/literals.html" rel="nofollow">meta-characters</a> replaced. It will not convert things into ranges (which I think is fine - doing so smells like premature optimization to me). You can do some post tests for <em>simple</em> set cases - like matching <code>sb</code> against digits, non-digits, etc, but unless you know that's going to buy you a lot of performance (or the simplification is the point of this program), I wouldn't bother.</p> <p>If you really want to do ranges, you could instead <code>sourceString.toCharArray()</code>, sort that, iterate deleting repetitions and doing some sort of range check and replacing meta characters as you add the contents to <code>StringBuilder</code>.</p> <p>EDIT: I actually kind of liked the <code>toCharArray</code> version, so pseudo-coded it out as well:</p> <pre><code>//...check for empty here, if not... char[] sourceC = sourceString.toCharArray(); Arrays.sort(sourceC); lastC = sourceC[0]; StringBuilder sb = new StringBuilder("["); StringBuilder range = new StringBuilder(); for (int i=1; i&lt;sourceC.length; i++) { if (lastC == sourceC[i]) continue; if (//.. next char in sequence..//) //..add to range else { // check range size, append accordingly to sb as a single item, range, etc } lastC = sourceC[i]; } </code></pre>
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    1. POHow to create a Pattern matching given set of chars?
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    1. USCarl
    1. USCarl
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    1. CO*"It will not convert things into ranges (which I think is fine - doing so smells like premature optimization to me)."* - This way I'd quickly end with 64k char long regexes as I use the complement sets.
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      1. USmaaartinus
 

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