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5122992
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0
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2011-02-25T21:37:31.820
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2011-02-25T21:37:31.820
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<p>The below code provides a few different ways of specifying database settings, including allowing old, Django 1.2-style <code>DATABASE_FOO</code> declarations:</p> <pre><code># Settings with no underscores in their names apply to the "default" # database out-of-the-box DATABASE_ENGINE = 'sqlite3' DATABASE_NAME = 'foo.sqlite' DATABASE_USER = '' DATABASE_PASSWORD = '' DATABASE_HOST = '' DATABASE_PORT = '' # Since this setting has underscores in it, it needs to be specified the # long way to disambiguate DATABASE_default_SUPPORTS_TRANSACTIONS = True # Specifying any settings for a database will implicitly copy everything # else from default. DATABASE_baz_NAME = 'baz.sqlite' # Databases can also be defined with Django 1.2-style dicts DATABASE_bar = { 'NAME': 'bar.sqlite', } # Empty dicts will create complete clones of default DATABASE_clone = {} </code></pre> <p>...and here's the implementation:</p> <pre><code>databases = {} database_global_settings = set([ 'DATABASE_ROUTERS', ]) current_settings = globals() for (k, v) in current_settings.items(): if k in database_global_settings: continue if k.startswith('DATABASE_'): if k.count('_') >= 2: (dummy_label, dbname, variable) = k.split('_', 2) if not dbname in databases: databases[dbname] = {} databases[dbname][variable] = v elif isinstance(v, dict): (dummy_label, dbname) = k.split('_', 1) if dbname in databases: databases[dbname].update(v) else: databases[dbname] = v else: # legacy configuration for default database dbname = 'default' (dummy_label, variable) = k.split('_', 1) if not dbname in databases: databases[dbname] = {} databases[dbname][variable] = v del globals()[k] for database_name in databases: if database_name != 'default': for (k, v) in databases['default'].iteritems(): databases[database_name].setdefault(k, v) DATABASES = databases </code></pre>
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1. PODjango - building settings.DATABASES dict programatically
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