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POHTML POST and fetch array
 

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    <p>I have two problems here:<br> <strong>1.</strong> I have a problem with the value of the checkbox<br> <strong>2.</strong> I have a problem with the mysql_fetch_array($variable, ASSOC); method --> all the data from my database are VARCHAR type</p> <p><strong>1.</strong> All the variable with, at the end 'Cb', signified that this value is from a checkbox of a FORM. If a checkbox is checked, it means that the row (ex: Username) will be in the Select method for my Database (ex: SELECT Username FROM...)</p> <p>I receive this Error 1. Undefined index: fonctionCb in C:\wamp\www\Projet Compte Utilisateur\manip_liste.php on line 7 2. Undefined variable: tab in C:\wamp\www\Projet Compte Utilisateur\manip_liste.php on line 14 ...etc from all the checkbox <strong>if they are not checked</strong> .. here is my PHP code</p> <pre><code>&lt;?php $prep = ""; if(!$_POST['username']) echo 'Nom d\'utilisateur manquant'; if(($_POST["userCb"]) &amp;&amp; ($_POST["suffixeCb"]) &amp;&amp; ($_POST["fonctionCb"]) &amp;&amp; ($_POST["passwordCb"])){ $prep = " * "; $tab = "User SUFFIXE SITE FONCTION PASSWD"; } else{ if($_POST["userCb"]){ $prep += "username ,"; $tab += "USER "; } if($_POST["suffixeCb"]){ $prep += "suffixe ,"; $tab += "SUFFIXE "; } if($_POST["passwordCb"]){ $prep += "password ,"; $tab += "PASSWD "; } if($_POST["siteCb"]){ $prep += "siteWeb ,"; $tab += "SITE "; } if($_POST["fonctionCb"]){ $prep += "fonction "; $tab += "Fx "; } }//ELSE require("db_action.php"); //Require in the database connection. $bd = db_open(); $data = db_select($prep, $_POST["username"]); //Envoie des variables à afficher et du Username pour le SELECT echo "'$tab'"; echo "'$data'"; ?&gt; </code></pre> <p><strong>2.</strong> The second ERROR and also I got this error from the fetch_array method Error: Warning: mysql_fetch_array() expects parameter 1 to be resource, string given in C:\wamp\www\Projet Compte Utilisateur\db_action.php on line 68</p> <p>Here is the code from my method</p> <pre><code>function db_select($prep, $username){ $querycon = "SELECT '$prep' FROM info_compte WHERE username = '$username'"; if(!mysql_query($querycon)){ echo "Il n\'y a aucun '$username' dans la base de données"; $response = ""; } else{ while ($row = mysql_fetch_array(mysql_query($querycon), MYSQL_ASSOC)) printf("%s %s %s %s %s", $row["username"], $row["suffixe"], $row["password"], $row["siteWeb"], $row["fonction"]); //The PRINTF dont work } return $response; }//db_select </code></pre> <p>Thank you all to answer and i specify that i'm a beginner in practice who wants to learn ..</p>
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    1. COMind not shouting?
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    2. COI'm sorry, that was not my intention
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    3. CO@ThorDozer: You should be concatenating strings with `.=` rather than `+=`. Also, try using something along the lines of `isset()` to check if a value is set. And I'm assuming your `$tab` variable is not being set as that if conditional is failing, therefore your attempts at concatenating are throwing errors.
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