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POEffective Java Item #77 - Serialization of singleton objects - Why should I have to use readResolve?
 

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    <p><a href="http://www.amazon.co.uk/Effective-Java-Edition-Joshua-Bloch/dp/0321356683/ref=sr_1_1?ie=UTF8&amp;qid=1336435020&amp;sr=8-1" rel="nofollow">Effective Java</a> #77 states that we have to use <code>readResolve</code> to preserve the Singleton guarentee during serialization. They have used the example.</p> <pre><code>public class Elvis implements Serializable{ public static final Elvis INSTANCE = new Elvis(); private Elvis() { ... } public void leaveTheBuilding() { ... } </code></pre> <p>and they suggest using</p> <blockquote> <p>If the Elvis class is made to implement Serializable, the following readResolve method suffices to guarantee the singleton property:</p> </blockquote> <pre><code>// readResolve for instance control - you can do better! private Object readResolve() { // Return the one true Elvis and let the garbage collector // take care of the Elvis impersonator. return INSTANCE; } </code></pre> <blockquote> <p>This method ignores the deserialized object, returning the distinguished Elvis instance that was created when the class was initialized.</p> </blockquote> <ul> <li>Now the question is does serialization loads the class again to have two instance of Elvis? </li> <li>If the class is loaded only once then we should be having only one instance of Elvis since static fields are not serialized and are not restored during deserialization and</li> <li>From where does the other Elvis instance comes which is made eligble for garbage collection by readResolve (prevented from escaping the deserializtaion process). Can this be explained?</li> </ul>
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