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2011-02-21T16:24:42.800
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2017-05-23T12:31:11.777
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There's no particular rules about absolute versus relative with Ant. You should avoid hard-coding absolute paths if possible - to make your build more portable. If you have to use absolute paths for some part of the build, try to construct them - say from the <code>${basedir}</code> of the project - so that changes are easier to make. Two things that may be useful for converting absolute paths to relative paths for use in filesets and the like: <ul> <li>the <a href="http://ant.apache.org/manual/Tasks/property.html" rel="nofollow noreferrer"><code>property</code> task</a> supports an attribute <code>relative=</code> that can be used to convert from an absolute path to relative.</li> <li>the <a href="http://ant.apache.org/manual/Tasks/pathconvert.html" rel="nofollow noreferrer"><code>pathconvert</code> task</a> can be used to do the same, when there are several absolute paths in one property.</li> </ul> Examples: <pre><code> <property name="myprop" value="${basedir}/x" /> <property name="myprop2" value="${basedir}/x:${basedir}/y" />  <property name="myprop_rel" location="${myprop}" relative="yes"/>  <path id="mypath2" path="${myprop2}" /> <pathconvert property="myprop2_rel" refid="mypath2" pathsep=","> <map from="${basedir}/" to="" /> </pathconvert> <fileset id="my_fileset" dir="." includes="${myprop2_rel}" /> </code></pre> In response to a comment: I'm not aware of a simple way to get the longest common prefix directory of a fileset in Ant, but here's a macro wrapping a script task that does what you might call 'shrink wrapping'. You call it with a reference to the 'input' fileset, and the name of the property to set. <pre><code><macrodef name="common-prefix-dir"> <attribute name="refid" /> <attribute name="outputproperty" /> <sequential> <script language="javascript"><![CDATA[ srcFiles = project.getReference( "@{refid}" ) .getDirectoryScanner( project ) .getIncludedFiles( ); if ( srcFiles.length > 0 ) { prefix = "" + srcFiles[0]; for ( i = 0; i < srcFiles.length; i++ ) { while ( prefix.length && srcFiles[i].substr( 0, prefix.length ) != prefix ) { prefix = prefix.substr( 0, prefix.length - 1); } if ( !prefix.length ) { break; } } } else { prefix = ""; } prefix = prefix.substring( 0, prefix.lastIndexOf( '/' ) ); project.setProperty( "@{outputproperty}", prefix ); ]]></script> </sequential> </macrodef> </code></pre> (This was derived from a <a href="https://stackoverflow.com/questions/1336207/finding-common-prefix-of-array-of-strings/1336357#1336357">php implementation</a>.) You can try it out with something like: <pre><code><property name="my.dir" location="...your dir here..." /> <fileset id="my.fs" dir="${my.dir}">  </fileset> <echo message="Input fileset is: '${toString:my.fs}'" /> <common-prefix-dir refid="my.fs" outputproperty="prefix" /> <echo message="Longest common prefix is: '${prefix}'" /> </code></pre> The <code>pathconvert</code> task can now be used to create a shrink-wrapped fileset: <pre><code><pathconvert property="shrink" refid="my.fs" pathsep=","> <map from="${my.dir}/${prefix}/" to="" /> </pathconvert> <fileset id="my.fs.out" dir="${my.dir}/${prefix}" includes="${shrink}" /> <echo message="Shrink-wrapped fileset is: '${toString:my.fs.out}'" /> </code></pre>
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1. POAnt create filesets, dirsets from (absolute) properties
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1. USmartin clayton
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1. COwhen there are several absolute paths in one property, is there a way to get the greatest common contiguous prefix (this would be the basedir)?
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 USalem0lars
2. CO@alem0lars - your comment is worthy of its own question. I've added a candidate solution.
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