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    <p><strong>This transformation</strong>:</p> <pre><code>&lt;xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"&gt; &lt;xsl:output omit-xml-declaration="yes" indent="yes"/&gt; &lt;xsl:strip-space elements="*"/&gt; &lt;xsl:key name="kLineById0Id1" match="line[field[@id=2]]" use="concat(field[@id=0],'+',field[@id=1])"/&gt; &lt;xsl:template match= "line[field[@id=2] and generate-id() = generate-id(key('kLineById0Id1', concat(field[@id=0], '+',field[@id=1]) )[1]) ] "&gt; &lt;xsl:element name="type-{field[@id=0]}"&gt; &lt;document&gt; &lt;xsl:value-of select="field[@id=1]"/&gt; &lt;/document&gt; &lt;sum&gt; &lt;xsl:value-of select= "sum(key('kLineById0Id1', concat(field[@id=0], '+',field[@id=1]) ) /field[@id=2] ) "/&gt; &lt;/sum&gt; &lt;/xsl:element&gt; &lt;/xsl:template&gt; &lt;xsl:template match="text()"/&gt; &lt;/xsl:stylesheet&gt; </code></pre> <p><strong>when applied on the provided XML document:</strong></p> <pre><code>&lt;document&gt; &lt;line id="0"&gt; &lt;field id="0"&gt;MAR&lt;/field&gt; &lt;field id="1"&gt;doc1&lt;/field&gt; &lt;field id="2"&gt;2&lt;/field&gt; &lt;/line&gt; &lt;line id="1"&gt; &lt;field id="0"&gt;MAR&lt;/field&gt; &lt;field id="1"&gt;doc2&lt;/field&gt; &lt;field id="2"&gt;3&lt;/field&gt; &lt;/line&gt; &lt;line id="2"&gt; &lt;field id="0"&gt;AAA&gt;&lt;/field&gt; &lt;field id="1"&gt;doc4&lt;/field&gt; &lt;/line&gt; &lt;line id="3"&gt; &lt;field id="0"&gt;MAR&lt;/field&gt; &lt;field id="1"&gt;doc1&lt;/field&gt; &lt;field id="2"&gt;4&lt;/field&gt; &lt;/line&gt; &lt;/document&gt; </code></pre> <p><strong>produces the wanted, correct result:</strong></p> <pre><code>&lt;type-MAR&gt; &lt;document&gt;doc1&lt;/document&gt; &lt;sum&gt;6&lt;/sum&gt; &lt;/type-MAR&gt; &lt;type-MAR&gt; &lt;document&gt;doc2&lt;/document&gt; &lt;sum&gt;3&lt;/sum&gt; &lt;/type-MAR&gt; </code></pre> <p><strong>Explanation</strong>: The <strong><a href="http://www.jenitennison.com/xslt/grouping/muenchian.html" rel="nofollow">Muenchian method for grouping</a></strong> is used with the key defined as the concatenation of two elements.</p>
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    1. USDimitre Novatchev
    1. USDimitre Novatchev
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    1. CO+1. Beat me for seconds :) Though I used consecutive predicates and push-style instead of concatenaded key.
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    2. COthanks for answer!!!
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    3. CO@Flack: Actually my solution does a little-bit more than the OP asks, but in this case produces what he wants. :)
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