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POBest way to write a function that takes in a timeout (posix C)
 

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  1. POBest way to write a function that takes in a timeout (posix C)
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    <p>So I have an embedded Linux device that is connected to a motor controller via a serial port. I am writing an interface library which makes a lot of nice generic functions which other programs will call. One of which is a function to run the program that is currently on the controller's flash disk:</p> <pre><code>int run_motor_program(int serial_fd, char *label, timeout); </code></pre> <p>The general pseudocode for this function is:</p> <pre><code>call write(serial_fd, "start program at `label`") perform a couple read()'s / write()'s to check whether program has started on the motor controller do /* some stuff */ while(program is running AND timeout hasn't exceeded) If the timeout exceeded, kill motor and return timeout error </code></pre> <p>The timeout in the above function definition is used in case something goes wrong while running the program on the motor controller. If the motor controller gets stuck in a longer loop than expected, I need the ability to stop program.</p> <p>The only ways I know for keeping track of a timeout are:</p> <p>1) Calling gettimeofday() before and during the loop to see if elapsed time is > timeout value passed in</p> <p>2) Calling clock_gettime() and basically doing the same as 1.</p> <p>3) Using timer_create() before the loop and timer_getoverrun() in the loop to check if the time has elapsed (this seems to be the most elegant solution, but I can't seem to get timer_getoverrun() to work with SIGEV_NONE [I don't want to use signals]).</p> <p>Which of these (or if anyone has any other suggestions) is the best way to handle including a timeout in a function? I really only need resolution down to the millisecond.</p>
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