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    <p>Store a array of characters that is the same length as the secret word. Initialize the characters to <code>*</code> and when a match is found, using <code>[indexOf][1]</code>, reveal the found characters:</p> <pre><code>String secretWord = userInput.next(); int len = secretWord.length(); //Store the length which will be used to see if puzzle was solved. char[] temp = new char[len]; //Store a temp array which will be displayed to the user for(int i = 0; i &lt; temp.length; i++) //initialize the array { temp[i] = '*'; } System.out.print("\n"); System.out.print("Word to date: "); while (attempts &lt;= 10 &amp;&amp; attempts &gt; 0) { System.out.println("\nAttempts left: " + attempts); System.out.print("Enter letter: "); String test = userInput.next(); if(test.length() != 1) { System.out.println("Please enter 1 character"); continue; } char testChar = test.charAt(0); //Find matches int foundPos = -2; int foundCount = 0; //How many matches did we find while((foundPos = secretWord.indexOf(testChar, foundPos + 1)) != -1) { temp[foundPos] = testChar; //Update the temp array from * to the correct character foundCount++; len--; //Decrease overall counter } if(foundCount == 0) { System.out.println("Sorry, didn't find any matches for " + test); } else { System.out.println("Found " + foundCount + " matches for " + test); } //Print for(int i = 0; i &lt; temp.length; i++) { System.out.print(temp[i]); } System.out.println(); if(len == 0) { break; //Solved! } attempts--; } if(len == 0) { System.out.println("\n---------------------------"); System.out.println("Solved!"); } else { System.out.println("\n---------------------------"); System.out.println("Sorry you didn't find the mystery word!"); System.out.println("It was \"" + secretWord + "\""); } </code></pre>
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    1. POSimple Java Hangman Assignment
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    1. USThe Scrum Meister
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    1. COIs it possible to do that without using arrays?
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      1. USJordan
    2. CO@jordan Everything is possible, Store a copy of the user-visible string. but Why???
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    3. COGiving the answer is not helping a novice learn *how* to come up with an answer.
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      1. USc_maker
 

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