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    <p>I would use two data structures --- a <strong>queue</strong> (e.g. <a href="http://java.sun.com/javase/6/docs/api/java/util/ArrayDeque.html" rel="noreferrer"><code>ArrayDeque</code></a>) for storing objects whose subobjects are to be visited, and a <strong>set</strong> (e.g. <a href="http://java.sun.com/javase/6/docs/api/java/util/HashSet.html" rel="noreferrer"><code>HashSet</code></a>) for storing all visited objects without duplication.</p> <pre><code>Set visited = new HashSet(); // all visited objects Queue next = new ArrayDeque(); // objects whose subobjects are to be visited // NOTE: At all times, the objects in "next" are contained in "visited" // add the first object visited.add(obj); Object nextObject = obj; while (nextObject != null) { // do stuff to nextObject for (Object o : nextObject.subobjects) { boolean fresh = visited.add(o); if (fresh) { next.add(o); } } nextObject = next.poll(); // removes the next object to visit, null if empty } // Now, "visited" contains all the visited objects </code></pre> <p><strong>NOTES:</strong></p> <ul> <li><a href="http://java.sun.com/javase/6/docs/api/java/util/ArrayDeque.html" rel="noreferrer"><code>ArrayDeque</code></a> is a space-efficient queue. It is implemented as a cyclic array, which means you use less space than a <a href="http://java.sun.com/javase/6/docs/api/java/awt/List.html" rel="noreferrer"><code>List</code></a> that keeps growing when you add elements.</li> <li>"<code>boolean fresh = visited.add(o)</code>" combines "<code>boolean fresh = !visited.contains(o)</code>" and "<code>if (fresh) visited.add(o)</code>".</li> </ul>
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Detail views are divided into sections. All the information in the data section comes from columns in the selected row. The other sections display data from other, related rows.

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