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    <p>Unfortunately @Dinesh/@DAJ's answer is incorrect. (@Romain's maybe too, but the wording is hard to parse.)</p> <p>Suppose you have a class <code>a.b.C</code> and you arrange that the same class gets loaded by two different classloaders. According to the specifications, you will end up with two distinct <code>Class</code> objects with the fully qualified name <code>a.b.C</code>, and from the type system perspective two distinct types. Each of the types will have a different set of static variables.</p> <p>The primary reference for this is <a href="http://java.sun.com/docs/books/jls/third_edition/html/typesValues.html#4.3.4" rel="nofollow">JLS 4.3.4</a> - paragraphs 2 and 3.</p> <p>You can infer that each reference type that is distinct (at runtime) will have a distinct set of statics from <a href="http://java.sun.com/docs/books/jls/third_edition/html/typesValues.html#4.12.3" rel="nofollow">JLS 4.12.3</a>, <a href="http://java.sun.com/docs/books/jls/third_edition/html/classes.html#8.3.1.1" rel="nofollow">JLS 8.3.1.1</a>, <a href="http://java.sun.com/docs/books/jls/third_edition/html/execution.html#12.4" rel="nofollow">JLS 12.4</a>, and other parts of the language spec.</p> <hr> <blockquote> <p>So basically, will the following statement always be true:</p> </blockquote> <pre><code>A.loadClass("MyClass").getField("myField").get(null) .equals(B.loadClass("MyClass").getField("myField").get(null)); </code></pre> <p>In general it won't. </p> <p>It will always be true in <em>some</em> cases, depending on how <code>MyClass</code> initializes <code>myField</code>. For instance, if the field is initialized to a literal String, then it will. </p> <p>(The trick to observing this is to arrange that <code>MyClass</code> is <em>actually loaded</em> by the two classloaders <code>A</code> and <code>B</code>, and not by a common ancestor classloader.)</p>
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    1. POWill other instances of a class be able to access a static variable in another?
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    1. USStephen C
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    1. COThanks so much :D Great answer. Now how do I give rep? O.o
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      1. USRyan Amos
 

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