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POreplacing dynamic text with an image
 

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    <p>I am trying to create a simplified code to insert images dynamically into a page based on user entry similar to BBCode.</p> <p>For example, if one of my users types "I like ducks [image]ducks[/image]", I want to explode the [image]ducks[/image], search MySQL for the keyword "ducks", pull the image path &amp; name from the database that matches, then display the image HTML code as well as the source to the image.</p> <pre><code>function image_replace($dimg){ list($title) = explode("[image]",$dimg); $query_image = mysql_query("SELECT * FROM images WHERE image_title LIKE '%$title%'"); $fetch_image = mysql_fetch_array($query_image); $image_path = $fetch_image['image_path']; $image_filename = $fetch_image['image_filename']; $image_source = $image_path.$image_filename; $dimg = str_replace("[image]","&lt;img src=\"$image_source\"&gt;", $dimg); $dimg = str_replace("[/image]","&lt;/img&gt;", $dimg); $dimg = str_replace("$title", "", $dimg); return $img; } image_replace($ducks); </code></pre> <p>The wall I'm hitting is how to replace the text inside a dynamically generated page if it exists - and leave the content alone if the code doesn't exist. Any ideas?</p> <hr> <p><strong>EDIT - Complicating the problem:</strong></p> <p>Thanks for helping! I used your input to make the following function:</p> <pre><code>function image_replace($string){ $matches = array(); preg_match('/\[image\](.*)\[\/image\]/', $string, $matches); $image = $matches[1]; $query_image = mysql_query("SELECT * FROM images WHERE image_title LIKE '%$image%'"); $fetch_image = mysql_fetch_array($query_image); $image_path = $fetch_image['image_path']; $image_filename = $fetch_image['image_filename']; $image_source = $image_path.$image_filename; $image_url = "&lt;img src=\"$image_source\"&gt;&lt;/img&gt;"; $new_string = preg_replace('/\[image\](.*)\[\/image\]/', $image_url, $string); return $new_string; } </code></pre> <p>I need this to work regardless of how many instances it occurs (thus if my user writes [image]duck[/image] then two sentences later writes [image]cow[/image], I want the function to replace both with their respective result). As it stands now, with more than one instance, it errors (not a valid SQL resource) which makes sense since preg_match only looks for one. I tried creating a loop (while &amp; foreach w/ preg_match_all) to try testing the concept - both created infinite loops and my web server admin isn't too happy :p</p>
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    1. COConsidering your new issue. I'll tinker with it a bit.
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      1. USAaron Hathaway
    2. COAlrighty my man, take a look at the edit for my answer and let me know if that does the trick!
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      1. USAaron Hathaway
 

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