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    <p>I would definitely not use a set - you don't need to sort it so no point in using a set. Set is implemented as a self-balancing tree usually, and the self-balancing algorithm is unnecessary in your case.</p> <p>If you're going to be doing this operation once, I would use a std::vector with remove_if (from &lt;algorithm>), followed by an erase. If you haven't used remove_if before, what it does is go through and shifts all the relevant items down, overwriting the irrelevant ones in the process. You have to follow it with an erase to reduce the size of the vector. Like so:</p> <pre><code>std::vector&lt;const char*&gt; files; files.erase(remove_if(files.begin(), files.end(), RemovePredicate()), files.end()); </code></pre> <p>Writing the code to do the same thing with a std::list would be a little bit more difficult if you wanted to take advantage of its O(1) deletion time property. Seeing as you're just doing this one-off operation which will probably take so little time you won't even notice it, I'd recommend doing this as it's the easiest way.</p> <p>And to be honest, I don't think you'll see that much difference in terms of speed between the std::list and std::vector approaches. The vector approach only copies each value once so it's actually quite fast, yet takes much less space. In my opinion, going up to a std::list and using three times the space is only really justified if you're doing a lot of addition and deletion throughout the entire application's lifetime. </p>
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