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POWhat is the meaning of this 'missing template arguments' C++ error
 

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  1. POWhat is the meaning of this 'missing template arguments' C++ error
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    <p>Ahh, C++ templates... </p> <blockquote> <p>The code I see,<br> makes sense to me,<br> but GCC...<br> it disagrees.</p> </blockquote> <p>The following code compiles and runs as expected, but if you uncomment that <code>#define</code>, you get the error, which I don't understand. The symbol <code>iterator</code> still has only one thing it can refer to: the typedef in the superclass. So I guess I have two questions: 1. What do the errors mean? 2. What is the best way to fix them.</p> <pre><code>#include &lt;map&gt; #include &lt;string&gt; #include &lt;cstdio&gt; using namespace std; // #define WITH_TEMPLATE 1 #ifdef WITH_TEMPLATE template &lt;class C&gt; struct MyClass : public map&lt;string, C&gt; #else struct MyClass : public map&lt;string, int&gt; #endif { bool haskey(const string &amp;s) { iterator it = find(s); return (it != end()); } }; int main() { #ifdef WITH_TEMPLATE MyClass&lt;int&gt; m; #else MyClass m; #endif m["test"] = 10; printf("%d %d\n", m.haskey("test"), m.haskey("no")); } </code></pre> <p>Errors from GCC:</p> <blockquote> <p>temp.cc: In member function ‘bool MyClass::haskey(const std::string&amp;)’:<br> temp.cc:18: error: <strong>missing template arguments before ‘it’</strong><br> temp.cc:18: error: expected `;' before ‘it’<br> temp.cc:19: error: ‘it’ was not declared in this scope<br> temp.cc:19: error: <strong>there are no arguments to ‘end’ that depend on a template parameter, so a declaration of ‘end’ must be available</strong><br> temp.cc:19: error: (if you use ‘-fpermissive’, G++ will accept your code, but allowing the use of an undeclared name is deprecated) </p> </blockquote>
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