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    <p>First download this JavaScript code, <a href="https://github.com/douglascrockford/JSON-js/blob/master/json2.js" rel="noreferrer">JSON2.js</a>, that will help us serialize the object into a string.</p> <p>In my example I'm posting the rows of a <a href="http://www.trirand.com/jqgridwiki/doku.php?id=start" rel="noreferrer">jqGrid</a> via Ajax:</p> <pre><code> var commissions = new Array(); // Do several row data and do some push. In this example is just one push. var rowData = $(GRID_AGENTS).getRowData(ids[i]); commissions.push(rowData); $.ajax({ type: "POST", traditional: true, url: '&lt;%= Url.Content("~/") %&gt;' + AREA + CONTROLLER + 'SubmitCommissions', async: true, data: JSON.stringify(commissions), dataType: "json", contentType: 'application/json; charset=utf-8', success: function (data) { if (data.Result) { jQuery(GRID_AGENTS).trigger('reloadGrid'); } else { jAlert("A problem ocurred during updating", "Commissions Report"); } } }); </code></pre> <p>Now on the controller:</p> <pre><code> [HttpPost] [JsonFilter(Param = "commissions", JsonDataType = typeof(List&lt;CommissionsJs&gt;))] public ActionResult SubmitCommissions(List&lt;CommissionsJs&gt; commissions) { var result = dosomething(commissions); var jsonData = new { Result = true, Message = "Success" }; if (result &lt; 1) { jsonData = new { Result = false, Message = "Problem" }; } return Json(jsonData); } </code></pre> <p>Create a JsonFilter Class (thanks to JSC reference).</p> <pre><code> public class JsonFilter : ActionFilterAttribute { public string Param { get; set; } public Type JsonDataType { get; set; } public override void OnActionExecuting(ActionExecutingContext filterContext) { if (filterContext.HttpContext.Request.ContentType.Contains("application/json")) { string inputContent; using (var sr = new StreamReader(filterContext.HttpContext.Request.InputStream)) { inputContent = sr.ReadToEnd(); } var result = JsonConvert.DeserializeObject(inputContent, JsonDataType); filterContext.ActionParameters[Param] = result; } } } </code></pre> <p>Create another class so the filter can parse the JSON string to the actual manipulable object: This class comissionsJS are all the rows of my jqGrid.</p> <pre><code> public class CommissionsJs { public string Amount { get; set; } public string CheckNumber { get; set; } public string Contract { get; set; } public string DatePayed { get; set; } public string DealerName { get; set; } public string ID { get; set; } public string IdAgentPayment { get; set; } public string Notes { get; set; } public string PaymentMethodName { get; set; } public string RowNumber { get; set; } public string AgentId { get; set; } } </code></pre> <p>I hope this example helps to illustrate how to post a complex object.</p>
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    1. POHow to post an array of complex objects with JSON, jQuery to ASP.NET MVC Controller?
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    1. USPeter Mortensen
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Detail views are divided into sections. All the information in the data section comes from columns in the selected row. The other sections display data from other, related rows.

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