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PO
primarykey
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4870370
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0
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0
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1
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2011-02-02T03:00:40.567
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0
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2011-02-02T03:41:58.863
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2011-02-02T03:41:58.863
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36305
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36305
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4868496
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2
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1
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text
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The currently accepted solution always displays the long days names in chronological order and in addition, it doesn't display repeating (with same code) days. Suppose we have the following XML document: <pre><code><days>STMSU</days> </code></pre> I. This XSLT 1.0 transformation: <pre><code><xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:my="my:my" exclude-result-prefixes="my" > <xsl:output omit-xml-declaration="yes" indent="yes"/> <my:days> <M>Monday</M> <T>Tuesday</T> <W>Wednesday</W> <R>Thursday</R> <F>Friday</F> <S>Saturday</S> Sunday </my:days> <xsl:key name="kLongByShort" match="my:days/*" use="name()"/> <xsl:variable name="vstylesheet" select="document('')"/> <xsl:template match="days"> <long-days> <xsl:call-template name="expand"/> </long-days> </xsl:template> <xsl:template name="expand"> <xsl:param name="pcodeString" select="."/> <xsl:if test="$pcodeString"> <xsl:variable name="vchar" select= "substring($pcodeString,1,1)"/> <xsl:for-each select="$vstylesheet"> <xsl:value-of select= "concat(key('kLongByShort',$vchar), substring(',',1,string-length($pcodeString)-1) ) "/> </xsl:for-each> <xsl:call-template name="expand"> <xsl:with-param name="pcodeString" select= "substring($pcodeString,2)"/> </xsl:call-template> </xsl:if> </xsl:template> </xsl:stylesheet> </code></pre> when applied on the above document, produces the wanted, correct result: <pre><code><long-days>Saturday,Tuesday,Monday,Saturday,Sunday</long-days> </code></pre> II. This XSLT 2.0 transformation: <pre><code><xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs"> <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:variable name="vshortCodes" as="xs:integer+" select="string-to-codepoints('MTWRFSU')"/> <xsl:variable name="vlongDays" as="xs:string+" select="'Monday','Tuesday','Wenesday','Thursday', 'Friday','Saturday','Sunday' "/> <xsl:template match="days"> <long-days> <xsl:for-each select="string-to-codepoints(.)"> <xsl:value-of separator="" select= "for $pos in position() ne last() return ($vlongDays[index-of($vshortCodes,current())], ','[$pos]) "/> </xsl:for-each> </long-days> </xsl:template> </xsl:stylesheet> </code></pre> when applied on the same XML document: <pre><code><days>STMSU</days> </code></pre> produce the wanted, correct result: <pre><code><long-days>Saturday,Tuesday,Monday,Saturday,Sunday</long-days> </code></pre>
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1. This table or related slice is empty.
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1. POConvert short form days of the week to day names in xslt
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1. USDimitre Novatchev
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1. USDimitre Novatchev
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1. CO+1 Mandatory XSLT 2.0 solution!
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