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POCounting Whitespace in Arguments in KSH?
 

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    <p>I am trying to allow strings that have whitespace in them to be counted as whole strings, rather than being parsed. This is what I would like to have happen:</p> <pre><code>$ ksh program.ksh "what up" File 'what up' not found. </code></pre> <p>And this is what I am getting:</p> <pre><code>$ ksh program.ksh "what up" File 'what' not found. File 'up' not found. </code></pre> <p>This is the code I've tried to make work:</p> <pre><code>wflag=false cflag=false while getopts "cw" opt; do case "$opt" in c) cflag=true ;; w) wflag=true ;; /?) ;; esac done </code></pre> <p>The problem lies when 1) I try something above like <code>ksh program.ksh "what up"</code>, and 2) when I try something like <code>ksh program.ksh "-w -c"</code>. The second one is most confusing, as when I print out <code>wflag</code> and <code>cflag</code> they are both true. Shouldn't <code>"-w -c"</code> be treated as a string here? It seems as though the kernel (is it the kernel doing the work here?) is parsing this, although that is exactly what I don't want; I want it to be treated as a string with whitespace. I have read through <a href="http://mywiki.wooledge.org/WordSplitting" rel="nofollow">WordSplitting</a> and ((the article on Arguments, wouldn't let me post it though)), and <em>think</em> I understand it. Clearly I must be missing something, or not really understanding it after all :P</p> <p>My instinct tells me there is something happening with <code>getopts</code> that automatically gets rid of any whitespace. I have tried <code>$(opt)</code> instead of <code>"$opt"</code>, as well as with curly braces and/or single quotes (I'm pretty sure single quotes is not what would work though). Alas, no cigar.</p> <p>Any help would be greatly appreciated, and thank you for reading through this wall of text.</p>
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