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POWhy doesn't java.lang.Number implement Comparable?
 

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    <p>Does anyone know why <code>java.lang.Number</code> does not implement <code>Comparable</code>? This means that you cannot sort <code>Number</code>s with <code>Collections.sort</code> which seems to me a little strange.</p> <p><strong>Post discussion update:</strong></p> <p>Thanks for all the helpful responses. I ended up doing <a href="http://radioeiffel.blogspot.com/2009/02/what-java-can-sort-numbers.html" rel="noreferrer">some more research about this topic</a>.</p> <p>The simplest explanation for why java.lang.Number does not implement Comparable is rooted in mutability concerns.</p> <p>For a bit of review, <code>java.lang.Number</code> is the abstract super-type of <code>AtomicInteger</code>, <code>AtomicLong</code>, <code>BigDecimal</code>, <code>BigInteger</code>, <code>Byte</code>, <code>Double</code>, <code>Float</code>, <code>Integer</code>, <code>Long</code> and <code>Short</code>. On that list, <code>AtomicInteger</code> and <code>AtomicLong</code> to do not implement <code>Comparable</code>.</p> <p>Digging around, I discovered that it is not a good practice to implement <code>Comparable</code> on mutable types because the objects can change during or after comparison rendering the result of the comparison useless. Both <code>AtomicLong</code> and <code>AtomicInteger</code> are mutable. The API designers had the forethought to not have <code>Number</code> implement <code>Comparable</code> because it would have constrained implementation of future subtypes. Indeed, <code>AtomicLong</code> and <code>AtomicInteger</code> were added in Java 1.5 long after <code>java.lang.Number</code> was initially implemented.</p> <p>Apart from mutability, there are probably other considerations here too. A <code>compareTo</code> implementation in <code>Number</code> would have to promote all numeric values to <code>BigDecimal</code> because it is capable of accommodating all the <code>Number</code> sub-types. The implication of that promotion in terms of mathematics and performance is a bit unclear to me, but my intuition finds that solution kludgy.</p>
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    1. USJulien Chastang
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    1. COJust to mention it: Comparing two arbitrary numbers is a possibly endless operation. See http://stackoverflow.com/questions/12561485/how-to-compare-two-numbers-in-java/12561805#12561805
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