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    <p>I think your example usage is quite good. Because if you would use an ordinary function pointer, and you then apply the address-of operator, you would get the address of the function pointer. Using a reference to function will do the expected thing, in that it returns a pointer to the function itself. </p> <p>I also can't think of many examples. Keeping function references, as you point out, has some ugly consequences. Another possibly unwanted consequence is, if kept as a class-member, your objects will be non-assignable if you don't write your own operator= and refrain from trying to re-assign the function-reference. </p> <p>I think most uses of function references are implicit, much like most uses of array-references - although much more so, when you accept arguments by-reference:</p> <pre><code>template&lt;typename T&gt; void do_something(T const&amp; t) { ... } </code></pre> <p>While accepting arrays by reference has the advantage of not losing their size information, accepting functions by reference explicitly doesn't seem to have an advantage (at least as far as I can see). I suppose the existence of function references largely is justified by the idealistic view of a reference as an <em>alias</em>-name of some object or function, together with the fact that it allows passing functions to such templates that accept their argument by reference.</p> <p>I would probably avoid using them if I wouldn't need them inevitably. Constant function pointers also provide non-reassignable callables, and will probably avoid confusions when other programmers, who possibly are not very familiar with this language niches, read your code. Worth to note that Vandervoorde &amp; Josuttis also recommend to avoid them to reduce confusion (in their book C++ Templates - The Complete Guide). </p>
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    1. COFunction pointers also have another advantage in that they can be made to look different from ordinary function calls: (*myFunc)(bar);
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    2. COaib. well the same is true for function references. you can even do (**************myFunc)(bar); it still works, because of the implicit conversion from function to function-pointer :) although i agree it looks funny
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    3. COHmm true, I did not think of that. You can do that with regular functions as well.
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