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    <p><del>replaceAll already works with StringBuffers anyway. (Well, to be precise, Matcher.replaceAll() uses StringBuffer, but String.replaceAll only delegates to Matcher.replaceAll() )</p> <p>For better performance you could build up the regex String by using a StringBuffer:</p> <pre><code> String head = "(?i)("; String tail = ")(?!([^&lt;]+)?&gt;&gt;)"; StringBuffer regex = new StringBuffer(); regex.append(head); regex.append(keyword); regex.append(tail); text.replaceAll(regex.toString(), "&lt;b&gt;$1&lt;/b&gt;"); </code></pre> <p>I don't really know, if there is a faster Replacement Implementation than the one of the Matcher class. But before you implement it yourself by using StringBuffer, I wanted to tell you, that it's already implemented that way.</del></p> <p>The following pseudocode might be buggy, but you could try it like this. (better performance is not guaranteed, but this should be the same as above without regex)</p> <pre><code>StringBuffer sb = new StringBuffer(text); int i = 0; int size = text.size() while(i&lt;size) { if(sb.charAt(i) == '&lt;') { increase i until you find '&gt;'; } if(sb.charAt(i) == keyword.charAt(0) { if(next chars of sb match next chars of keyword) { insert "&lt;b&gt;" before and "&lt;/b&gt;" after the keyword; size += 7; i += keyword.size() + 7; } } } </code></pre> <p>you might also want to take a look into the Matcher implementation of replaceAll: <a href="http://kickjava.com/src/java/util/regex/Matcher.java.htm" rel="nofollow">http://kickjava.com/src/java/util/regex/Matcher.java.htm</a></p>
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    1. POTurning replace regex into java algorithm
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    1. COadded an update
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    2. COThis should be really helpful: http://stackoverflow.com/questions/2861/options-for-html-scraping
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