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PONSRegularExpression to validate URL
 

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    <p>I found this regular expression on a website. It is said to be the best URL validation expression out there and I agree. Diego Perini created it.</p> <p>The problem I am facing is when trying to use it with <code>objective-C</code> to detect URLs on strings. I have tried using options like <code>NSRegularExpressionAnchorsMatchLines</code>, <code>NSRegularExpressionIgnoreMetacharacters</code> and others, but still no luck. </p> <p>Is the expression not well formatted for <code>Objective-C</code>? Am I missing something? Any ideas? </p> <p>I have tried John Gruber's regex, also, but it fails with some invalid URLs.</p> <pre><code> Regular Expression Explanation of expression ^ match at the beginning //Protocol identifier (?: (?:https?|ftp http, https or ftp ):\\/\\/ :// )? optional // User:Pass authentication (?: ^\\s+ non white spaces, 1 or more times (?: :^\\s* : non white spaces, 0 or more times, optionally )?@ @ )? optional //Private IP Addresses ?! Means DO NOT MATCH ahead. So do not match any of the following (?: (?!10 10 10.0.0.0 - 10.999.999.999 (?: \\.\\d{1,3} . 1 to 3 digits, three times ){3} ) (?!127 127 127.0.0.0 - 127.999.999.999 (?: \\.\\d{1,3} . 1 to 3 digits, three times ){3} ) (?!169\\.254 169.254 169.254.0.0 - 169.254.999.999 (?: \\.\\d{1,3} . 1 to 3 digits, two times ){2} ) (?!192\\.168 192.168 192.168.0.0 - 192.168.999.999 (?: \\.\\d{1,3} . 1 to 3 digits, two times ){2} ) (?!172\\. 172. 172.16.0.0 - 172.31.999.999 (?: 1[6-9] 1 followed by any number between 6 and 9 | or 2\\d 2 and any digit | or 3[0-1] 3 followed by a 0 or 1 ) (?: \\.\\d{1,3} . 1 to 3 digits, two times ){2} ) //First Octet IPv4 // match these. Any non network or broadcast IPv4 address (?: [1-9]\\d? any number from 1 to 9 followed by an optional digit 1 - 99 | or 1\\d\\d 1 followed by any two digits 100 - 199 | or 2[01]\\d 2 followed by any 0 or 1, followed by a digit 200 - 219 | or 22[0-3] 22 followed by any number between 0 and 3 220 - 223 ) //Second and Third Octet IPv4 (?: \\. . (?: 1?\\d{1,2} optional 1 followed by any 1 or two digits 0 - 199 | or 2[0-4]\\d 2 followed by any number between 0 and 4, and any digit 200 - 249 | or 25[0-5] 25 followed by any numbers between 0 and 5 250 - 255 ) ){2} two times //Fourth Octet IPv4 (?: \\. . (?: [1-9]\\d? any number between 1 and 9 followed by an optional digit 1 - 99 | or 1\\d\\d 1 followed by any two digits 100 - 199 | or 2[0-4]\\d 2 followed by any number between 0 and 4, and any digit 200 - 249 | or 25[0-4] 25 followed by any number between 0 and 4 250 - 254 ) ) //Host name | or (?: (?: [a-z\u00a1-\uffff0-9]+-? any letter, digit or character one or more times with optional - )* zero or more times [a-z\u00a1-\uffff0-9]+ any letter, digit or character one or more times ) //Domain name (?: \\. . (?: [a-z\u00a1-\uffff0-9]+-? any letter, digit or character one or more times with optional - )* zero or more times [a-z\u00a1-\uffff0-9]+ any letter, digit or character one or more times )* zero or more times //TLD identifier (?: \\. . (?: [a-z\u00a1-\uffff]{2,} any letter, digit or character more than two times ) ) ) //Port number (?: :\\d{2,5} : followed by any digit, two to five times, optionally )? //Resource path (?: \\/[^\\s]* / followed by an optional non space character, zero or more times )? optional $ match at the end </code></pre> <p><strong>EDIT</strong> I think I forgot to say that I am using the expression in the following code: (partial code) </p> <pre><code>NSError *error = NULL; NSRegularExpression *detector = [NSRegularExpression regularExpressionWithPattern:[self theRegularExpression] options:0 error:&amp;error]; NSArray *links = [detector matchesInString:theText options:0 range:NSMakeRange(0, theText.length)]; </code></pre>
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